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ehidna [41]
3 years ago
6

Jason is 6 feet tall, and at 6 pm, his shadow was 15 feet long. At the same time, a tree next to Jason had a 25-foot shadow. Wha

t is the height, in feet, of the tree?
Mathematics
1 answer:
IRISSAK [1]3 years ago
3 0

Answer:

10

Step-by-step explanation:

set up a ratio problem

6 feet/15 long shad= x/25 shad

15x = 150

x = 10

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Nostrana [21]

Answer:

w=-11/6

Step-by-step explanation:

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2 years ago
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Josh is painting all the walls in his room that is 3m x 4m and 2.75m high, How much paint in square feet is needed?
pantera1 [17]

Answer:

33

Step-by-step explanation:

3*4*2.75=33

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2 years ago
Write an addition equation or a subtraction equation (your choice!) to describe the diagram.​
harina [27]

Answer:

(-9) + (-2) = -11

Step-by-step explanation:

The first arrow on the number line starts from 0, moves downwards 9 units from 0.

We would write this as -9.

Also, the next arrow starts moves from -9, 2 units downwards.

We would write this as -2

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3 years ago
Which is the quotient for
mars1129 [50]

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i think its D

Step-by-step explanation:

D

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3 years ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
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