What is the relationship between the number of sides of the base of a prism and the number of lateral faces?

Mathematics

2 answers:

bezimeni [28]2 years ago

5 0

Answer: The number of sides of the base of a prism and the number of lateral faces is equal.

Step-by-step explanation:

Arte-miy333 [17]2 years ago

4 0

Answer:

Step-by-step explanation:

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Find the mode of the data.<br> 1, 2, 1, 3, 3, 4, 1<br> The mode is

drek231 [11]

Answer:

1 is the answer.

Step-by-step explanation:

The mode of a data set is the number that occurs most frequently in the set.

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2 years ago

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So when you are adding fractions how do you know when you need to simplify the numbers and how do you simplify?

rosijanka [135]

Let's look at an example.

We'll add the fractions 1/6 and 1/8

Before we can add, the denominators must be the same.

To get the denominators to be the same, we can...

multiply top and bottom of 1/6 by 8 to get 8/48
multiply top and bottom of 1/8 by 6 to get 6/48

At this point, both fractions involve the denominator 48. We can add the fractions like so

8/48 + 6/48 = (8+6)/48 = 14/48

Add the numerators while keeping the denominator the same the entire time.

The last step is to reduce if possible. In this case, we can reduce. This is because 14 and 48 have the factor 2 in common. Divide each part by 2.

14/2 = 7
48/2 = 24

The fraction 14/48 reduces to 7/24

Overall, 1/6 + 1/8 = 7/24

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2 years ago

The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow

Reika [66]

If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now $\bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
0=\frac{3w^2-6000000}{w^2}
\end{cases}$

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the $0=w^2\implies 0=w$ so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other