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3 years ago

10

For every 140 feet that Kelly rides on her bicycle, the wheels turn 20 times. About how many timed do the wheels turn in 5 miles

? ( 1 mile =5,280 feet )

2 answers:

Tamiku [17]3 years ago

7 0

Answer:

asnwer is in the pjcturw

alukav5142 [94]3 years ago

3 0

Answer:

184,800 times

Step-by-step explanation:

140/20=7 rotations in 1 foot.

5,280*7=36,960 times in 1 mile

36,960*5=184,800 times in 5 miles

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Factor:<br><br> 4b2−12b+9<br><br> A) (2b−3)2<br> B) (2b+3)2<br> C) (2b−3)(2b+3)<br> D) (2b−9)(2b−1)

tatuchka [14]

Answer:

A

Step-by-step explanation:

(2b-3)^2 = (2b-3)(2b-3) = 4b^2-12b+9

7 0

3 years ago

Factor 15x^2y^2 - 3x^3y + 75x^4. Show your work. Need to show work and please be 100% honest. Only answer if you know how. Will

snow_lady [41]

Answer:

3x^2(25x^2−xy+5y^2)

Step-by-step explanation:

I copied it into MathPapa and it is always correct. It gave me that

7 0

3 years ago

Read 2 more answers

Shawna says her mug holds 100 milliliters.

Aleks04 [339]

Answer:

In 1 liter there are 1000 milliliters so because 100 ≠ 1000 the answer is <u>no</u>

8 0

2 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Explain how to multiply 15 3/4 x 8

max2010maxim [7]

Answer:

Step-by-step explanation:

The easiest way is to use the distributive rule. 15¾ = 15+ ¾

15¾*8 = (15+¾)8 = 15*8 + ¾*8 = 120+6 = 126

3 0

3 years ago