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3 years ago

-4r-11=4r+21 pls help

Mathematics

2 answers:

Masja [62]3 years ago

8 0

-4r-11=4r+21

Move 4r to the other side

Sign changes from +4r to -4r

-4r-4r-11=4r-4r+21

-4r-4r-11=21

-8r-11=21

Move -11 to the other side

Sign changes from -11 to +11

-8r-11+11=21+11

-8r=21+11

-8r=32

Divide both sides by -8

-8r/-8=32/-8

Answer: r=-4

gizmo_the_mogwai [7]3 years ago

4 0

Answer:

r=-4

Step-by-step explanation:

-4r-11=4r+21

Subract 4r from each side.

-4r-4r-11=21

-8r-11=21

Add 11 to each side.

-8r=21+11

-8r=32

Divide both sides by -8.

r= $\frac{32}{-8}$

r=-4

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3 years ago

The data show the average monthly temperatures for two cities over a 6-month period. City 1: {20, 24, 40, 63, 76, 89} City 2: {4

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Answer:

The MAD of city 2 is less than the MAD for city 1, which means the average monthly temperature of city 2 vary less than the average monthly temperatures for City 1.

Step-by-step explanation:

For comparing the mean absolute deviations of both data sets we have to calculate the mean absolute deviation for both data sets first,

So for city 1:

$Mean = x1 = \frac{20+24+40+63+76+89}{6}$

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Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored as the deviation is the distance of value from the mean and it cannot be negative. For this purpose absolute is used)

$20-52 = -32=32\\24-52=-28=28\\40-52=-12=12\\63-52=11\\76-52=24\\89-52=37$

The deviations will be added then. $Mean Absolute Deviation = \frac{32+28+12+11+24+37}{6} \\=\frac{144}{6}\\=24$

So the mean absolute deviation for city 1 is 24 ..

For city 2:

$Mean = x2 = \frac{41+50+58+62+72+83}{6}$

$x2 = \frac{366}{6}$

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Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored)

$41-61=-20=20\\50-61=-11=11\\58-61=-3=3\\62-61=1\\72-61=11\\83-61=22$

The deviations will be added then. $Mean Absolute Deviation = \frac{20+11+3+1+11+22}{6} \\=\frac{68}{6}\\=11.33$

So the MAD for city 2 is 11.33 ..

So,

The MAD of city 2 is less than the MAD for city 1, which means the average monthly temperature of city 2 vary less than the average monthly temperatures for City 1.

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3 years ago

Read 2 more answers

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1 year ago

If x = 39, y = 58, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answ

KatRina [158]

Answer: 1.64 units

Step-by-step explanation:

Given the following :

X = 39°

Y = 58°

AC = 4 units

Using triangle ABC with x = 39° and AC = 4UNITS,

USING THE Pythagoras, the SOHCAHTOA notation:

AC = opposite = 4units

AB = hypotenus

Sinθ = opposite / hypotenus

x = Θ = 39°

Sinx = opposite / hypotenus

Sin39° = 4 / AB

0.6293203 = 4 / AB

AB = (4 ÷ 0.6293203) = 6.3560629 units

Taking triangle ADC, with x = 58° and AC = 4UNITS,

AC = opposite = 4units

AD = hypotenus

Sinθ = opposite / hypotenus

y = Θ = 58°

Sinx = opposite / hypotenus

Sin58° = 4 / AD

0.8480480 = 4 / AD

AD = (4 ÷ 0.8480480) = 4.7167136 units

Difference between AB and AD

(6.3560629 - 4.7167136) = 1.6393493

= 1.64 units

6 0

3 years ago

-4r-11=4r+21 pls help ​

-4r-11=4r+21 pls help