Need help with 7 please?!

The price to ship a box varies directly as the weight of the box in pounds. A box that weighs 10 pounds costs $10.90 to ship.

xenn [34]

Well we can say 10.90/10 = the cost per pound to ship the item
we can infer this from the above text so
10.90/10 = 1.09.
So 1.09 * 37 = 40.33
$40.33
or 40 dollars and 33 cents to ship the second box with a weight of 37lb (pounds).

3 0

3 years ago

What is the mode of the following set of data? 34, 23, 12, 11, 11, 25, 25, 26, 25, 27, 30

Olin [163]

1 - B

Mode - The mode the number that appears most often in a data set. In this question, 25 was repeated 3 times and no other ones where repeated 3 times. Thats why 25 is the mode.

2 - D

Median - The middle number of a data set that is arranged from least to greatest.

3 - True

There is no mode because all of the numbers only appear once.

4 - A

5 - C

4 0

3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

Meg has 15 marbles. Roberto has 3 times as many marbles as Meg. How many does Roberto have?

ValentinkaMS [17]

Answer:

Step-by-step explanation:

15*3=45

5 0

2 years ago

Read 2 more answers

A summer pool membership costs $275 for 3 months. You can also buy an individual pass for $12.50. If you plan to go to the pool

Leona [35]

12.50 x 8 = 100
100 x 3 = $300
so $275 for 3 months would be the better deal but i’m not sure if by each month u meant 3 months or the whole year. if the whole year was the case it would be
12.50 x 8 = 100
100 x 12 = $1,200
275 x 4 = $1,100
so in that case $275 for 3 months would still be the better deal.

5 0

2 years ago