The correct answer is 12
Set up a ratio and then solve. See paper attached. (:
Show that if p(a) ⊂ p(b) then a ⊂ b.
<span>I will assume p() means power set. </span>
<span>proof: let x∈a, then {x} ∈ p(a) and so by hypothesis {x} ∈ p(b). However {x} could not be in p(b) unless x∈b. This shows that each element of a is an element of b and hence a ⊂ b.
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The complete pattern is: 512, 256, 128, 64, 32, 16, 8, ( and extended ) 4, 2, 1!
I do this pattern in my head literally all the time!
