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devlian [24]
4 years ago
14

What is the definition of efficent

Physics
1 answer:
nika2105 [10]4 years ago
8 0

Efficient: the measure of how much energy is used in a process.

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The count rate of a radioactive source decreases from 1600 counts per minute to 400 counts per minute in 12 hours. What is the h
kirill115 [55]

Answer:

t_{1/2}=6 h

Explanation:

Let's use the decay equation.

A=A_{0}e^{-\lambda t}

Where:

  • A is the activity at t time
  • A₀ is the initial activity
  • λ is the decay constant

We know that \lambda=\frac{ln(2)}{t_{1/2}}

So we have:

\lambda=\frac{ln(A/A_{0})}{t}

\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}

t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}

t_{1/2}=6 h

Therefore, the half-life of the source is 6 hours.

I hope it helps you!

4 0
3 years ago
What is the correct definition of civics?
RSB [31]

Answer:

the definition of civics is the study of the rights and duties of citizenship.

so the answer is B.

hope this helps.

4 0
3 years ago
Read 2 more answers
calculate minimum number of incident photons per area and of the minimum dose needed to visualize an object of 1 mm squared usin
Lynna [10]

Answer:

minimum number of photon is 4.05 × 10^{7}

Explanation:

given data

energy = 50 keV = 50 × 10^{3} eV =  50 × 10^{3} × 1.602× 10^{-19}  J

thickness = 10^-3

contrast = 1%

to find out

number of incident photons

solution

we know here equation that is

E  = n  × h  × ν   .......................1

put here all these value

50 × 10^{3} = n × 6.6× 10^{-34} × c/ 1× 10^{-3}

50 × 10^{3} × 1.602× 10^{-19}  = n × 6.6× 10^{-34} ×( 3 × 10^{8} / 1× 10^{-3})

solve it and find n

n = 4.05 × 10^{7}

so here minimum number of photon is 4.05 × 10^{7}

3 0
3 years ago
There are 15 water molecules in the air, and the relative
AlexFokin [52]

30 30 30 30 30 30 30 30 30 30

6 0
2 years ago
A particle (mass = 5.0 g, charge = 40 mC) moves in a region of space where the electric field is uniform and is given by Ex = –2
taurus [48]

Answer: 40m

Explanation: Distance is a function of speed/ velocity and time.

From the question the velocity along the z axis is given as 20 m/s at t = 0 secs We were ask to calculate the distance travelled when t = 2secs.

Recall that,

Velocity = distance travelled / time

Since we're calculating for distance we make it subject of formula;

Distance travelled = velocity * time

= 20m/s * 2s

= 40meter.

3 0
3 years ago
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