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goldfiish [28.3K]
3 years ago
12

What is the correct definition of civics?

Physics
2 answers:
kow [346]3 years ago
8 0

Answer:

The study of the rights and duties of citizens.

Explanation:

Civics is something each immigrant wants to take if they want citizenship in the country they immigrant too. These classes provide things such as basic history of the nation, basic reading and grammar, as well as any other extras they decide to teach. These classes would help the to-be-citizen in taking their citizen test, in which their background is checked, and they are tested on what they learned.

~

RSB [31]3 years ago
4 0

Answer:

the definition of civics is the study of the rights and duties of citizenship.

so the answer is B.

hope this helps.

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There are four stages in an economic recovery. In which order do these stages occur
Klio2033 [76]

The answer is 2,1,3,2

1. increased production 2. rising demand (occurs twice) 3. increased hiring

hope this helps :)

7 0
4 years ago
A high-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. the flywheel has mass 40.0 kg and
tangare [24]
<span>The flywheel is solid cylindrical disc. Moment of inertial = ½ * mass * radius^2 Mass = 40.0 kg Radius = ½ * 76.0 cm = 38 cm = 0.38 meter Moment of inertial = ½ * 41 * 0.36^2 Convert rpm to radians/second The distance of 1 revolution = 1 circumference = 2 * π * r The number of radians/s in 1 revolution = 2 * π 1 minute = 60 seconds 1 revolution per minute = 2 * π radians / 60 seconds = π/30 rad/s Initial angular velocity = 500 * π/30 = 16.667 * π rad/s 170 revolutions = 170 * 2 * π = 340 * π radians The flywheel’s initial angular velocity = 16.667 * π rad/s. It decelerated at the rate of 1.071 rad/s^2 for 48.89 seconds. θ = ωi * t + ½ * α * t^2 θ = 16.667 * π * 48.89 + ½ * -1.071 * 48.89^2 2559.9 - 1280 θ = 1280 radians</span>
4 0
3 years ago
Help me i suck at physics ;-;
Alex_Xolod [135]

force= mass x acceleration= 0.2 x 20= 4 N

(N stands for newton btw)

7 0
3 years ago
Read 2 more answers
which one of these represent total momentum of a system of two particles traveling one against the other?
antoniya [11.8K]

The total momentum of a system is the vector sum of all the individual masses that comprise the system.

Moreover, To calculate the total momentum of two objects during a collision, add their individual momentums. You can calculate the momentum for each object using the formula p=mv, where p is the momentum, m is the mass, and v is the velocity. The law of conservation of momentum can be expressed as follows. For a collision between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

You can learn more about this at:

brainly.com/question/20301772#SPJ4

5 0
1 year ago
Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 3.44 kg and rotate with
Free_Kalibri [48]

Answer:

(a) 20,154.1 J

(b) 95,223.5 J

Explanation:

The expression for the moment of inertia for the uniform solid cylinder is as follows;

I= \frac{1}{2}mr^{2}

Here, I is the moment of inertia, r is the radius and m is the mass of the object.

The expression for the rotational kinetic energy is as follows;

K= \frac{1}{2}I\omega ^{2}

Here, K is the rotational kinetic energy and \omega is the angular velocity.

(a)

Calculate the moment of inertia of the smaller solid cylinder.

I= \frac{1}{2}mr^{2}

Put m= 3.44 kg and r= 0.356 m.

I= \frac{1}{2}(3.44)(0.356)^{2}

I= 0.218 kg m^{2}

Calculate the rotational kinetic energy of the smaller cylinder.

K= \frac{1}{2}I\omega ^{2}

Put I= 0.218 kg m^{2} and \omega = 430 rads^{-1}.

K= \frac{1}{2}(0.218)(430) ^{2}

K= 20,154.1 J

Therefore, the rotational kinetic energy for the smaller cylinder is 20,154.1 J.

(b)

Calculate the moment of inertia of the larger solid cylinder.

I= \frac{1}{2}mr^{2}

Put m= 3.44 kg and r= 0.775 m.

I= \frac{1}{2}(3.44)(0.775)^{2}

I= 1.03 kg m^{2}

Calculate the rotational kinetic energy of the smaller cylinder.

K= \frac{1}{2}I\omega ^{2}

Put I= 1.03 kg m^{2} and \omega = 430 rads^{-1}.

K= \frac{1}{2}(1.03)(430) ^{2}

K= 95,223.5 J

Therefore, the rotational kinetic energy for the larger cylinder is 95,223.5 J.

7 0
4 years ago
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