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3 years ago

a student weighing 490 N stands on a spring scale on earth. what is the students mass(gravity is 9.8 m/s

Physics

1 answer:

True [87]3 years ago

4 0

Answer:

Mass, m of the student is 50kg.

Explanation:

Given the following data;

Weight of student = 490N

Acceleration due to gravity = 9.8m/s

Weight is the product of the mass of an object or body multiplied by gravity.

Mathematically, weight is;

$W = mg$

Where;

W represents the weight of a body measured in Newton.

m represents the mass of a body measured in kilograms.

a represents acceleration due to gravity measured in metre per seconds.

$m = \frac{W}{g}$

$m = \frac{490}{9.8}$

Mass, m = 50kg.

Therefore, the mass of the student is 50kg.

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Strike441 [17]

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<u>Explanation:</u>

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3 years ago

A tabletop gamer has designed a game that requires three dice to be thrown onto a tray with a measurement grid. To add an extra

Airida [17]

Answer:

The resulting coordinate is $(x,y) = (-0.170 \ m , -0.038 \ m )$

Explanation:

From the question we are told that

The mass of the first dice is $m_1 = 11.10 \ g$

The mass of the second dice is $m_2 = 15.10 \ g$

The mass of the third dice is $m_3 = 18.90 \ g$

The coordinate of the first dice is $(x_1, y_1) = (0.3150\ m , -0.4990 \ m )$

The coordinate of the second dice is $(x_2,y_2) = (-0.4050 \ m , 0.4850 \ m )$

The coordinate of the third dice is $(x_3 , y_3) = (-0.1150 \ m , -0.1850\ m )$

Generally the resulting coordinate of the center of mass of the dice in the x-axis is mathematically evaluated as

$x\ cm = \frac{m_1 * x_1 + m_2 * x_2 + m_3 * x_3}{m_1 + m_2 +m_3 }$

i.e the summation of the moments about their x-axis divided by the magnitude of their masses

substituting values

$x\ cm = \frac{11.0 * 0.3150 + 15.10 * (-0.4050) + 18.90 * (-0.1150)}{11.100 + 15.10 +18.90 }$

$x\ cm = -0.170 \ m$

Generally the resulting coordinate of the center of mass of the dice in the y-axis is mathematically evaluated as

$y\ cm = \frac{m_1 * y_1 + m_2 * y_2 + m_3 * y_3}{m_1 + m_2 +m_3 }$

$y\ cm = \frac{ 11.10 * (-0.4990) + (15.10) * (0.4850) + (18.90) * (-0.1850)}{ 11.10 + 15.10 +18.90 }$

$y\ cm = -0.038 \ m$

Thus the resulting coordinate is $(x,y) = (-0.170 \ m , -0.038 \ m )$

4 0

3 years ago

Explain in your OWN words what erosion mass wasting means

marishachu [46]

Explanation:

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3 years ago

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Rama09 [41]

Answer:

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2 years ago

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