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DaniilM [7]
3 years ago
14

An object begins x=75.2 m and undergoes a displacement of -48.7 m. what is its final position?

Physics
1 answer:
xz_007 [3.2K]3 years ago
8 0

Answer:

26.5 m

Explanation:

x_{o} = initial position of the object = 75.2 m

x  = final position of the object

d  = displacement of the object = - 48.7  

Displacement of the object is given as the difference of final and initial position of the object

d = x - x_{o}

Inserting the values

- 48.7 = x - 75.2

x = 26.5 m

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A machine does 50 J of Work on a 10 Kg Object. What is the Change in the Objects Total Energy?
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The change in the total energy of the object is zero (0).

The given parameters:

work done by the machine, W = 50 J

mass of the object, m = 10 kg

To find:

the change in the total energy of the object

The change in the total energy of the object is the difference between the objects initial energy due to its position and the work done on the object.

Based on work energy-theory, the work done on the object is equal to the energy of the object.

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Thus, the change in the total energy of the object is zero (0).

Learn more here: brainly.com/question/20377140

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2 years ago
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Answer:

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3 years ago
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A 3.0 kg object is loaded into a toy spring gun, and the spring has a spring constant 750N/m. The object compresses the spring b
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Answer:

Explanation:

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angle of gun, θ = 30°

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(b) Let v be th evelocity of ball at the tim eof launch.

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h = \frac{v^{2}Sin^{2}\theta}{2g}

h = \frac{1.265^{2}Sin^{2}30}{2\times 9.8}

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h = 2 cm  

4 0
3 years ago
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