1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DaniilM [7]
3 years ago
14

An object begins x=75.2 m and undergoes a displacement of -48.7 m. what is its final position?

Physics
1 answer:
xz_007 [3.2K]3 years ago
8 0

Answer:

26.5 m

Explanation:

x_{o} = initial position of the object = 75.2 m

x  = final position of the object

d  = displacement of the object = - 48.7  

Displacement of the object is given as the difference of final and initial position of the object

d = x - x_{o}

Inserting the values

- 48.7 = x - 75.2

x = 26.5 m

You might be interested in
A clam of mass 0.12 kg dropped by a seagull takes 3.0 s to hit the ground. [Neglect friction.]
inna [77]
This is a defective, misleading question, and should never be asked in a Physics class.

There is no such thing as the force due to the impact.

If you know how long it takes the clam to stop once it begins to hit the dirt,
then you can calculate the impulse transferred to it, and tease a force out
of that.  But the question doesn't give us the time. 

It depends on the material of the surface.  Was the clam dropped onto dirt ? 
Into a dumpster ?  Onto grass ?  Concrete ?  Styrofoam ?  Mud ?  The answer
is different in each case, and we still need to know the short length of time
AFTER it first encountered whatever surface brought it to rest.

I would kick this question back to the Physics teacher.  It's meaningless,
and the longer you try to work on it, the more nonsense you'll plant into
your head that'll need to be dug out later.
8 0
3 years ago
At the top of a giant swing on the gymnastics high bar, candy's velocity is 1 m/s, and she is 3.5 m high. if candy's mass is 50
Allushta [10]
The total mechanical energy is the sum of the kinetic energy and the gravitational potential energy:
E=K+U= \frac{1}{2}mv^2 +mgh
where m=3.5 kg is Candy's mass, v=1 m/s is her velocity and h=3.5 m is her height. If we replace these numbers, we find the mechanical energy of the system:
E= \frac{1}{2} (50 kg)(1m/s)^2 + (50 kg)(9.81 m/s^2)(3.5 m)=1742 J =1.74 kJ
6 0
3 years ago
HELP WILL GIVE BRAINLIEST IF CORRECT
PolarNik [594]

Answer:

the answer is 1.35. Have a nice day!!

3 0
3 years ago
Read 2 more answers
the (speed) of an object is a vector quantity that tells us the speed and direction of an objects momentum is this correct? If n
Ivenika [448]

Answer:

sorry kailangan points wh

7 0
3 years ago
Read 2 more answers
Describe the climate and name the climate zone at alaska; portland, oregon; and key west, florida.
Tpy6a [65]
Alaska-                   Subartic Climate 
Portland, Oregon-  Marine West Coast Climate
Key West, Florida- Tropical Savannah Climate
3 0
3 years ago
Other questions:
  • How are emotional and intellectual health related
    12·1 answer
  • In which activity is no work done?
    15·2 answers
  • An alien spaceship is 300 m above the ground and moving at a constant velocity of 250 m/s upwards. How high above the ground is
    7·1 answer
  • How do find the force of buoyancy ​
    12·1 answer
  • (a) It is difficult to extinguish a fire on a crude oil tanker, because each liter of crude oil releases 2.80×107J of energy whe
    10·2 answers
  • A 0.025 g sample of o is injected into a 1.00 l flask at 30.0c. what forms of water will be present at equilibrium? vapor pressu
    8·1 answer
  • What is electric force ​
    8·1 answer
  • An earth satellite in an elliptical orbit travels slowest when it is
    5·1 answer
  • orange light has a wavelength, λ, of 6.0 × 10-7 m. in a vacuum, the speed of light, c, is 3.0 × 108 m/s. what is the frequency,
    10·1 answer
  • t is 165 cm from your eyes to your toes. you are standing 200 cm in front of a tall mirror. how far is it from your eyes to the
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!