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mamaluj [8]
3 years ago
12

Find the Y component of 35m/s at 57 degrees from the X-axis.

Physics
1 answer:
rosijanka [135]3 years ago
3 0

Answer:

35m/s[57o].

X = 35*Cos57 =

Y = 35*sin7 =Explanation:

learn man but there u go

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jok3333 [9.3K]
True......I would say...
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Someone pls answer this
andriy [413]

Answer:

<em>The speed of metal block B is 5 m/s after the collision</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of them all

P=m_1v_1+m_2v_2+...+m_nv_n

If some collision occurs, the velocities change to v' and the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

In a system of two masses, we have:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.

After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':

\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}

Substituting the given values:

\displaystyle v'_2=\frac{3.2*4+1.6*0-3.2*1.5}{1.6}

\displaystyle v'_2=\frac{8}{1.6}

\displaystyle v'_2=5\ m/s

The speed of metal block B is 5 m/s after the collision

8 0
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Answer:

guard cell

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Force = 7kN <br> Pressure = 1mPa<br> Area = ?
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Answer:

7 m^2

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Area is 7 meters squared

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