part A)
![\bf \begin{array}{|c|cccccc|ll} \cline{1-7} x&8&27&64&125&&x\\ \cline{1-7} y&\stackrel{\sqrt[3]{8}}{2}&\stackrel{\sqrt[3]{27}}{3}&\stackrel{\sqrt[3]{64}}{4}&\stackrel{\sqrt[3]{125}}{5}&&\sqrt[3]{x} \\ \cline{1-7} \end{array}~\hspace{10em}y = \sqrt[3]{x}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Ccccccc%7Cll%7D%20%5Ccline%7B1-7%7D%20x%268%2627%2664%26125%26%26x%5C%5C%20%5Ccline%7B1-7%7D%20y%26%5Cstackrel%7B%5Csqrt%5B3%5D%7B8%7D%7D%7B2%7D%26%5Cstackrel%7B%5Csqrt%5B3%5D%7B27%7D%7D%7B3%7D%26%5Cstackrel%7B%5Csqrt%5B3%5D%7B64%7D%7D%7B4%7D%26%5Cstackrel%7B%5Csqrt%5B3%5D%7B125%7D%7D%7B5%7D%26%26%5Csqrt%5B3%5D%7Bx%7D%20%5C%5C%20%5Ccline%7B1-7%7D%20%5Cend%7Barray%7D~%5Chspace%7B10em%7Dy%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
part B)
f(x) = 10 + 20x
so if you rent the bike for a few hours that is
1 hr.............................10 + 20(1)
2 hrs..........................10 + 20(2)
3 hrs..........................10 + 20(3)
so the cost is really some fixed 10 + 20 bucks per hour, usually the 10 bucks is for some paperwork fee, so you go to the bike shop, and they'd say, ok is 10 bucks to set up a membership and 20 bucks per hour for using it, thereabouts.
f(100) = 10 + 20(100) => f(100) = 2010.
f(100), the cost of renting the bike for 100 hours.
Given that: Triangle ABC is translated to triangle A'B'C' by the transformation
The points are A(4, -4), B(2, -5), C(0, 6), D(-2, 5).
To find: Coordinates of A'.
The coordinates of A are (4,-4).
Using the given rule of transformation, we get
On simplification, we get
Therefore, the coordinates of point A' are (6,-9).
M = -8/5
hope this helps :)
Assuming the first function is y = 4x2<span> + 1, and the second y = 4x</span>2<span> then the first graph is 1 unit higher than the second.</span>
Answer:
I just answered it on your other question but
4. AB+BC=AC
6. AC=BD
Step-by-step explanation:
