There are 12 months, 7/12 have 31 days. You would have a 7/12 probability of choosing one with 31 days if it is random.
Answer:
The answer to your question is: 40.8 g of NaN₃
Step-by-step explanation:
NaN₃ mass = ?
nitrogen = 1.2 moles
Equation
2NaN₃ ⇒ 2Na + 3N2
2 moles of NaN₃ ----------------- 3 moles of N₂
x ------------------ 1.2 moles of N₂
x = (1.2 x 2) / 3
x = 2.4/ 3
x = 0.8 moles of NaN₃
MW NaN₃ = 23 + 28
= 51 g
51 g of NaN₃ ----------------- 1 mol
x ----------------- 0.8 mol
x = (0.8 x 51) / 1
x = 40.8 g of NaN₃
Answer:
If the lifetime of batteries in the packet is 40.83 hours or more then, it exceeds for 5% of all packages.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 15
Standard Deviation, σ = 1
Sample size = 4
Total lifetime of 4 batteries = 40 hours
We are given that the distribution of lifetime is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling:
We have to find the value of x such that the probability is 0.05
P(X > x) = 0.05
Calculation the value from standard normal z table, we have,
Hence, if the lifetime of batteries in the packet is 40.83 hours or more then, it exceeds for 5% of all packages.
Answer:
1.) (11, -7/3), 2.) No solution. 3.) (1, 3)
Step-by-step explanation:
1.)
2x + 3y = 15
x - 3y = 18
Solve...use elimination method
2x + x + 3y - 3y = 15 + 18
3x = 33
x =11
11 - 3y = 18
-3y = 7
y = -7/3
(11, -7/3)
---------------------------------------
2.) y = 4x + 4
y = 4x - 4
Use substitution.
4x + 4 = 4x - 4
4 = -4 FALSE NO Solution
3.) y = 5- 2x
4x + 3y = 13
Can use elimination method
2y = 10 - 4x
add it to 4x + 3y = 13
10 + 3y = 2y + 13
y = 3
3 = 5 - 2x
x = 1
(1, 3)
Answer:
No, he doesn't it would be 5 cents over the amount of money he has.
