Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x</span>∆x+∆x^2-2∆x)/<span>∆x
Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.
Making the limit of </span><span>∆x=0, we get 2x-2.</span>
Answer:no not in amillion years
Step-by-step explanation:hehe nahhhhhhhhhh lll
The annual interest rate is 3.5%.
Solution:
Given Interest (I) = $26.25
Principal (P) = $500
Time (t) = 18 months
Rate of interest (r) = ?
Time must be in years to find the rate per annum.
1 year = 12 months
Divide the time by 12.
Time (t) = years
Now, find the rate of interest using simple interest formula.
<u>Simple interest formula:</u>
⇒ r = 3.5%
Hence the annual interest rate is 3.5%.
Converting all to improper fractions
31/10s = 31/5
5×31s=31×10
155s = 310
s=310/155= 2
20/9=-4/5m
5×20=-4×9m
100=-36m
m=100/-36 = 72 28/36 = 72 7/9
-14/5=-7/2n
-14×2=5×-7n
-28=-35n
n =-28/-35
n=28/35
Answer:
2m+12
Step-by-step explanation:
add like terms
2m+12