Solve the linear programming problem by the method of corners. Maximize P = 6x − 4y subject to x + 2y ≤ 50 5x + 4y ≤ 145 2x + y
≥ 25 y ≥ 7, x ≥ 0 The maximum is P = 1 Incorrect: Your answer is incorrect. at (x, y) = .
1 answer:
Answer:
The maximum is P=112.4 at (23.4,7)
Step-by-step explanation:
From the graph, the coordinates of the vertices of the feasible region are:
(0,25)
(9,7)
(23.4, 7)
(15,17.5)
Substituting these values in the objective function, P.
At (0,25), P = 6x − 4y=6(0)-4(25)=-100
At (9,7), P = 6x − 4y=6(9)-4(7)=26
At (23.4,7), P = 6x − 4y=6(23.4)-4(7)=112.4
At (15,17.5), P = 6x − 4y=6(15)-4(17.5)=20
Since the objective is to maximize,
The maximum is P=112.4 at (23.4,7)
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