120º is 1/3 of a complete revolution of 360º. So the area of this sector should be 1/3 the area of the complete circle.
A circle with radius 9 has area 9^2 π = 81π.
So the sector has area 81π/3.
Put another way: The area <em>A</em> of a circular sector and its central angle <em>θ</em> (in degrees) occur in the same ratio as the area of the entire circle with radius <em>r</em> according to
<em>A</em> / <em>θ </em>º = (π <em>r </em>^2) / 360º
==> <em>A</em> = π/360 <em>θ r</em> ^2
In this case, <em>r</em> = 9 and <em>θ</em> = 120º, so
<em>A</em> = π/360 * 120 * 81 = 81π/3
Answer:
12.5
Step-by-step explanation:
first you do the one in the 40-15 then you add 50 the you divide by 6
9514 1404 393
Answer:
A 7/25
Step-by-step explanation:
The cosine of an angle is equal to the sine of its complement. In a right triangle, angle A is the complement of angle B. So, ...
cos(A) = sin(B)
cos(A) = 7/25
Answer:slope =3/4 y-intercept=3
Step-by-step explanation: