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stiks02 [169]
3 years ago
15

A carpenter worked for 4 days to finish a repair job. She charged $825 for 15 hours plus $278 for materials. What is the carpent

er's rate per hour?
Mathematics
2 answers:
Levart [38]3 years ago
7 0

Answer:  Carpenter's rate per hour is $73.53.

Step-by-step explanation:

Since we have given that

Number of hours she charged for = 15 hours

Cost for 15 hours = $825

Cost of materials = $278

Total cost she charged is given by

\$825+\$278\\\\=\$1103

So, Carpenter's rate per hour is given by

\frac{Total\ amount}{Number\ of\ hours}\\\\=\frac{1103}{15}\\\\=\$73.53

Hence, Carpenter's rate per hour is $73.53.

harina [27]3 years ago
3 0
29. A carpenter worked for 4 days to finish a repair job. She charged $825 for 15 hours plus $278 for materials. What is the carpenter's rate per hour? Let’s start solving: => 825 dollars + 278 dollars = 1 103 dollars is the total payment a carpenter have received => 15 hours is the total hours he worked => 1 103 / 15 = 73.5 dollars per hour. This is already including the material or equipment fee.
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Answer:

We need to conduct a hypothesis in order to check if the technique performs differently than the traditional method, the system of hypothesis would be:  

Null hypothesis:\mu =10.1  

Alternative hypothesis:\mu \neq 10.1

t=\frac{10.5-10.1}{\frac{1.4}{\sqrt{12}}}=0.990    

p_v =2*P(t_{(11)}>0.990)=0.343    

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL  reject the null hypothesis, so we can't conclude that the technique performs differently than the traditional method at 10% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=10.5 represent the sample mean

s=1.4 represent the sample standard deviation

n=12 sample size  

\mu_o =10.1 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the technique performs differently than the traditional method, the system of hypothesis would be:  

Null hypothesis:\mu =10.1  

Alternative hypothesis:\mu \neq 10.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{10.5-10.1}{\frac{1.4}{\sqrt{12}}}=0.990    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=12-1=11  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(11)}>0.990)=0.343  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL  reject the null hypothesis, so we can't conclude that the technique performs differently than the traditional method at 10% of signficance.  

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Answer:

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Step-by-step explanation:

Given equation:

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Solution:

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We have:

6x+1\°=3x+11\°

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