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natima [27]
3 years ago
14

What is 5,392,029,004 in word form?????

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0
Five billion three hundred ninety two million twenty nine thousand and four
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A park is 4 times as it is wide. If the distance around the park is 12.5 kilometers what is the area of the park
MaRussiya [10]

Answer:

6.25 km

Step-by-step explanation:

Here is the correct question: A park is 4 times as long as it is wide. If the distance around the park is 12.5 kilometers, what is the area of the park?

Given: Perimeter (Distance) of the park= 12.5 km

Considering park is in rectangular shape.  

Let the width of park be x

∴ as given length will be 4x.

Formula for perimeter of rectangle =2\times (length + width)

Perimeter is given 12.5 km

⇒ 12.5= 2\times (4x+x)

⇒ 12.5= 10x

∴ x= 1.25 km, which means width is 1.25 km and length is 5 km.

Now, finding the area of park

Formula; Area of rectangle= length\times width

∴ Area of rectangle= 5\times 1.25 = 6.25 km

∴Area of park will be 6.25 km.

6 0
3 years ago
21 and 22 are complementary angles. The measure of Z1 is 45 The measure of Z2 is 3x°. Find the value of x. The figure is not dra
Alex

9514 1404 393

Answer:

  x = 15

Step-by-step explanation:

<u>Given</u>:

  ∠1 + ∠2 = 90°

  ∠1 = 45°

  ∠2 = 3x°

<u>Find</u>:

  x

<u>Solution</u>:

  Using the given values in the given equation, we have ...

  45° +3x° = 90°

  15 + x = 30 . . . . . . divide by 3°

  x = 15 . . . . . . . . . . . subtract 15

6 0
2 years ago
When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
12x^6y^-4z^2/3x^2y^-6z^3
11111nata11111 [884]

Answer:

dont click the link!!

Step-by-step explanation:

5 0
3 years ago
Please help me out with this
nignag [31]
P(score > 334) ≈ .0227501319

3 0
3 years ago
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