Answer:
A horizontal line; a melting ice cube.
Step-by-step explanation:
A constant interval appears as a horizontal line. The graph in the interval has a slope m = 0.
Here's an example of a constant interval.
You take an ice cube from the freezer and place it in a container on the counter.
The temperature of the ice cube is -5 °C. The ice cube will warm to 0 °C, and then it will start to melt. While it is melting, the temperature is constant at 0 °C.
When the ice has completely melted, the water will start warming to room temperature.
A plot of <em>temperature vs. time</em> would look something like the graph below.
The interval AB, where the ice is melting, is a constant interval.
I think that the answer is A.
A repeating decimal is a decimal that has a digit, or a group of digits, that repeat forever. A terminating decimal, on the other hand, is a decimal that ends. To find which decimals are repeating and which ones are terminal, we are going to simplify our fractions, and express them in decimal form:
![\frac{25}{60} = \frac{5}{12} =0.4166666666...](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%7D%7B60%7D%20%3D%20%5Cfrac%7B5%7D%7B12%7D%20%3D0.4166666666...)
6 is repeating forever, so this is a repeating decimal.
![\frac{17}{60} =0.283333333....](https://tex.z-dn.net/?f=%20%5Cfrac%7B17%7D%7B60%7D%20%3D0.283333333....)
3 is repeating forever, so this is a repeating decimal.
![\frac{31}{44} =07045454545....](https://tex.z-dn.net/?f=%20%5Cfrac%7B31%7D%7B44%7D%20%3D07045454545....)
45 is repeating forever, so this is a repeating decimal.
![\frac{54}{72} = \frac{3}{4} =0.75](https://tex.z-dn.net/?f=%20%5Cfrac%7B54%7D%7B72%7D%20%3D%20%5Cfrac%7B3%7D%7B4%7D%20%3D0.75)
No digit is repeating forever, so this is a terminating decimal.
We can conclude that:
Repeating decimals:
![\frac{25}{60}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%7D%7B60%7D%20)
,
![\frac{17}{60}](https://tex.z-dn.net/?f=%20%5Cfrac%7B17%7D%7B60%7D%20)
, and
Terminating decimals:
For the first question, you just need to plug the values and solve for k:
![11 = \dfrac{3000}{500}+k \iff 11=6+k \iff k=11-6=5](https://tex.z-dn.net/?f=11%20%3D%20%5Cdfrac%7B3000%7D%7B500%7D%2Bk%20%5Ciff%2011%3D6%2Bk%20%5Ciff%20k%3D11-6%3D5)
Now we know that
, so the cost of 200 cards will be
![y = \dfrac{3000}{200}+5 = 15+5=20](https://tex.z-dn.net/?f=y%20%3D%20%5Cdfrac%7B3000%7D%7B200%7D%2B5%20%3D%2015%2B5%3D20)
Finally, if we want the cost to be 7 we're asking
![7=\dfrac{3000}{x}+5 \iff \dfrac{3000}{x}=2 \iff x = \dfrac{3000}{2}=1500](https://tex.z-dn.net/?f=7%3D%5Cdfrac%7B3000%7D%7Bx%7D%2B5%20%5Ciff%20%5Cdfrac%7B3000%7D%7Bx%7D%3D2%20%5Ciff%20x%20%3D%20%5Cdfrac%7B3000%7D%7B2%7D%3D1500)
Answer:
ddddddddddddStep-by-step explanation: