F=ar^t if the half-life is 96 years...
.5=r^96
ln(.5)=96lnr
ln(.5)/96=lnr
r=e^((ln.5)/96)
f=800e^(336(ln.5)/96)
f=70.71
So about 71mg will remain after 336 years.
Answer:
(b) 0.30 atm
Step-by-step explanation:
Given data
Initial pressure= 1.2atm
Initial volume= 1.0L
Final volume= 4.0L
Final pressure= ???
Let us apply the gas formula to find the Final pressure
P1V1= P2V2
Substitute
1.2*1= x*4
Divide both sides by 4
1.2/4= x
x= 0.3atm
Hence the final pressure is 0.3 atm
A,,,,they are multiples of the lengths indicated
Answer:
The answer is 1/9 ⇒ the second answer
Step-by-step explanation:
* In the exponential functions we have some rules
(1) b^(-m) = 1/(b^m) (for all nonzero real numbers b)
- If we have negative power we reciprocal the base
to get positive power
(2) (b^m)^n = b^(mn)
- If we have power over power we multiply them
* In our problem: 
- At first change 27 to b^n
∵ 27 = 3 × 3 × 3 = 3³
∴ 
* Lets use rule (2)
∴
⇒ 3 × -2/3 = -2
* Use rule (1)
∴
⇒ reciprocal the fraction to change the sig of the power
* The answer is 1/9
Answer:
-36s + 54
Step-by-step explanation:
−9(5s − 6) + 9s =
-45s + 54 + 9s =
-36s + 54