3 years ago

HELPPPPPPP PLEASE. IM SO CONFUSED IM WEIRD

Mathematics

1 answer:

Jlenok [28]3 years ago

4 0

I think that the answer is A.

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In the middle school debate club, 40% of the members are in sixth grade. If there are 12 sixth graders in the debate club, how m

lbvjy [14]

Answer is definitely this
Answer=30

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3 years ago

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Distributive property to solve -9(2-p)

Nikitich [7]

Answer:

9p−18

Step-by-step explanation:

Expand by distributing terms

(−9×2 ) (−9×−p)

Simplify
−18−9×−p

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−18−(−9p)

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9p−18

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2 years ago

Find the square root of the following by prime factorization method.

weeeeeb [17]

Answer:

$\boxed{=65}\\$

Step-by-step explanation:

$\begin{array} {c|c}4225&5\\845&5\\169&13\\13&13\\1\\\end{array}\\\\\\4225=5^2*13^2\\\\\sqrt{4225} \\\\=5^{\frac{2}{2} }*13^{\frac{2}{2} }\\\\=5*13\\\\\boxed{=65}\\$

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3 years ago

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The perimeter of a football field is 920 feet. The width is 60 feet more than one-third of the length. What are the dimensions o

Step2247 [10]

Given:

Perimeter of a football field = 920 feet.

The width is 60 feet more than one-third of the length.

To find:

The dimensions of a football field.

Solution:

Let the length of the field be x.

Then, width = $\dfrac{1}{3}x+60$

We know that,

$Perimeter = 2( length + width)$

$920 = 2(x+\dfrac{1}{3}x+60)$

$920 = 2(\dfrac{4}{3}x+60)$

$920 =\dfrac{8}{3}x+120$

Subtract both sides by 120.

$920-120 =\dfrac{8}{3}x+120-120$

$800 =\dfrac{8}{3}x$

Multiply both sides by 3.

$2400 =8x$

Divide both sides by 8.

$300 =x$

Now,

$Length = 300\text{ feet}$

$Width=\dfrac{1}{3}(300)+60$

$Width=100+60$

$Width=160\text{ feet}$

Therefore, the length and width of the football field are 300 feet and 160 feet respectively.

7 0

3 years ago

Please help I will give brainliest.

Rasek [7]

1. -11x +-27
2. 5
Hope this helps.

3 0

3 years ago