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EastWind [94]
3 years ago
7

Which tool would you use to measure the mass of a mobile phone

Mathematics
2 answers:
iragen [17]3 years ago
6 0
<span>Since on the Earth, mass = weight, you can use a scale.


hope that helped</span>
SVEN [57.7K]3 years ago
5 0
You could use a weighing scale, but if the mobile is easy to measure, you can use ruler, take the measurements of length width and height, and use formula for volume
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wilhelmina has 8.3 ounces of peanut butter.if she makes 5 sandwijes with an equal amount ofbpeanut butter on each,how much peanu
kotykmax [81]

Peanut butter: 8.3 ounces

Sandwich: 5

Divide 8.3 by 5, for equal amount of peanut butter on each sandwich.

8.3/5 = 1.66

She puts 1.66 ounces of peanut butter on each sandwich.

3 0
3 years ago
A circle has a circumference of 266.9 inches. What is the Diameter of this circle? What is the Radius? Use 3.14 as the approxima
Natali5045456 [20]

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r= 42.48 and d=84.96

Step-by-step explanation:

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4 0
3 years ago
Evaluate f+g^2-3g if f= 5 and g=2
Lady_Fox [76]

Answer:

The answer world be 3.

Step-by-step explanation:

5 + 2² - 3(2) = 3

3 0
3 years ago
Read 2 more answers
The cost for each soda is $2.25. If your friend Calvin buys a certain number of Coca-Colas (c) and Mountain Dews (m), which answ
levacccp [35]

Answer:

2.25(c+m)

Step-by-step explanation:

3 0
3 years ago
Please help!!!!!!!!!!!!
podryga [215]

Given : Fix amount charges = $200.

Each month additional charge = $50.

Let us assume number of months are taken by x.

So, we can setup a function as

Total charge  = Fix charge + each month charge * number of months.

f(x)  = 200 + 50*x

Or f(x) = 200 +5x.

Where function f is the total charge of x number of months.

The values of x's represents domain and function value represents range.

According to problem, it is said " first three months".

So, we need to take number of months as x=0,1,2,3.

And we need to find values of function for those x values.

On plugging x=0,1,2 and 3 we would get

f(0) = 200 +5(0) = 200 +0 = 200.

f(1) = 200 +5(1) = 200 +50 = 250.

f(2) = 200 +5(2) = 200 +100 = 300.

f(3) = 200 +5(3) = 200 +150 = 350.

We got function values 200,250,300 and 350.

Therefore, with respect to the given situation, the domain of the funtion is

{0,1,2,3} and Range { 200,250,300, 350}.

6 0
3 years ago
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