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EastWind [94]
3 years ago
7

Which tool would you use to measure the mass of a mobile phone

Mathematics
2 answers:
iragen [17]3 years ago
6 0
<span>Since on the Earth, mass = weight, you can use a scale.


hope that helped</span>
SVEN [57.7K]3 years ago
5 0
You could use a weighing scale, but if the mobile is easy to measure, you can use ruler, take the measurements of length width and height, and use formula for volume
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If sin(x) = M, with M &gt; 0, find the value of then sin(x - pi) =
Alexus [3.1K]

Step-by-step explanation:

sin(x) = M, M > 0

= sin(x - π)

= sin(x)cos(π) - cos(x)sin(π)

= sin(x).(-1) - cos(x).0

= -sin(x) - 0

= -sin(x)

= -M

7 0
2 years ago
Water runs from a pump at a rate of 0.5 gallons per minute. At this rate, how long would it take to fill a tub with a 150-gallon
lutik1710 [3]

Answer:

300 min or 5 hours

Step-by-step explanation:

so if it pumps 0.5 gallons per minute than in 2 minutes it would pump 1 whole gallon so with that we know 1gallon=2 minutes.

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3 0
3 years ago
2 (01.05)
lord [1]

Answer:

  y +2 = 4(x -3)

Step-by-step explanation:

Point-slope form of the equation of a line with slope m through point (h, k) is ...

  y -k = m(x -h)

For m = 4 and (h, k) = (3, -2), the equation is ...

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3 0
3 years ago
Need a math genius for help
asambeis [7]

Answer:

5

Step-by-step explanation:

The answers equivilant to 3 are 1,5,7

Pick the angle is closer to the middle (interior). 5

7 0
3 years ago
Can you answer these please many thanks
givi [52]

Given: (a) 2(x+3)=2x+6 and (b) 4(y-3)=4y-12.

To find: The expanded form of the given expressions.

(c) 4(m+n)=4m+4n       (using a(b+c)=ab+ac)

(d) 3(5-q)=15-3q           (using a(b-c)=ab-ac)

(e) 5(2c+1)=10c+5          (using a(b+c)=ab+ac)

(f) 3(2x-5)=6x-15          (using a(b-c)=ab-ac)

(g) 7(4b-1)=28b-7          (using a(b-c)=ab-ac)

(h) 3(2x+y-5)=3((2x+y)-5)

⇒3(2x+y-5)=3(2x+y)-15         (using a(b-c)=ab-ac)

⇒3(2x+y-5)=6x+3y-15            (using a(b+c)=ab+ac)

(i) 2(6a-4b+3)=2((6a-4b)+3)

⇒2(6a-4b+3)=2(6a-4b)+6         (using a(b+c)=ab+ac)

⇒2(6a-4b+3)=12a-8b+6            (using a(b-c)=ab-ac)

(j)6(m+n+p)=6((m+n)+p)

⇒ 6(m+n+p)=6(m+n)+6p           (using a(b+c)=ab+ac)

⇒ 6(m+n+p)=6m+6n+6p            (using a(b+c)=ab+ac)

(k) y(y+2)=y^2+2y          (using a(b+c)=ab+ac)

(l) g(g-3)=g^2-3g           (using a(b-c)=ab-ac)

(m) n(4-n)=4n-n^2        (using a(b-c)=ab-ac)

(n) a(b+c)=ab+ac           (using a(b+c)=ab+ac)

(o) s(3s-4)=3s^2-4s        (using a(b-c)=ab-ac)

(p) 2x(x+5)=2x^2+10x     (using a(b+c)=ab+ac)

(q) 4y(x-3)=4xy-12y      (using a(b-c)=ab-ac)

(r) 5a(2b-5)=10ab-25a     (using a(b-c)=ab-ac)

(s) 4a(3b+2c)=12ab+8ac    (using a(b+c)=ab+ac)

(t) 5p(4p-5q)=20p^2-25pq    (using a(b-c)=ab-ac)

6 0
3 years ago
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