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natka813 [3]
3 years ago
12

If a triangle has a height of 12 inches in the base of 5 inches what is the area

Mathematics
1 answer:
tatiyna3 years ago
4 0
<span>The area of the triangle with height 12 inches and the base of 5 inches is 30 square inches. The area (A) of a triangle with height, h, and base, b, is: A = h * b / 2. We know that h = 12 in and that b = 5 in. Therefore, the area of this triangle will be: A = 12 in * 5 in / 2 = 60 in^2 / 2 = 30 in^2. The area of the triangle is 30 square inches.</span>
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Hi can you guys help me. The topic is similiar shapes in this case triangles do you guys know how to find a length. I got some p
Airida [17]

PR=18mm
AB=7mm

All lengths of triangle PRQ are twice the lengths of ACB





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3 years ago
If x is 4, what is:<br> x + 5<br><br><br> 3x:
kirill [66]

Answer:

1) x+5

(4)+5 =

9

2) 3x

3(4)

12

Step-by-step explanation:

5 0
3 years ago
What is the value of x in the equation 4x + 8y = 40, when y = 0.8?
Alona [7]
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8 0
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Read 2 more answers
Suppose 45% of the population has a college degree.
levacccp [35]

Using the normal distribution, there is a 0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

The proportion estimate and the sample size are given as follows:

p = 0.45, n = 437.

Hence the mean and the standard error are:

  • \mu = p = 0.45
  • s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.45(0.55)}{437}} = 0.0238

The probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3% is <u>2 multiplied by the p-value of Z when X = 0.45 - 0.03 = 0.42</u>.

Hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = (0.42 - 0.45)/0.0238

Z = -1.26

Z = -1.26 has a p-value of 0.1038.

2 x 0.1038 = 0.2076.

0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

More can be learned about the normal distribution at brainly.com/question/28159597

#SPJ1

8 0
2 years ago
What is the inequality for x and why ?
sveticcg [70]

-3x - 42 > 3 |+42

-3x > 45 |change the signs

3x < -45 |:3

x < -15 → x ∈ (-∞, -15)

3 0
4 years ago
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