All categories

3 years ago

If x=9, what is the value of y in the equation below??????y=8x-[1+4x] plz answer

Mathematics

2 answers:

nalin [4]3 years ago

6 0

35 is the answer :D have fun getting cheats on ur hw

PSYCHO15rus [73]3 years ago

4 0

8 times 9=72
1+4 times 8=37
72-37=35

You might be interested in

A train leaves Little Rock, Arkansas, and travels north at 75 kilometers per hour. Another train leaves at the same time and tr

Alecsey [184]

Answer:

Step-by-step explanation:

let time be x

total distance = 450

75x+75x=450

150x=450

x=3h

3 0

3 years ago

Read 2 more answers

Find the GCF for 15az and 25az

SOVA2 [1]

Answer:

The GCF for 15az and 25az is marked below.

15az = 3*5*a*z

25ab - 5*5*a*b

GCF = 5a

Step-by-step explanation:

Answers above! Hoped this helped :)

5 0

3 years ago

Read 2 more answers

A coach travels to the beach which is 576 KM away in 6 hours. If he is only allowed to travel at a maximum speed of 90 kph, did

Whitepunk [10]

Answer:

Yes

Step-by-step explanation:

576Km:6Hrs

576 divided by 6=96 km

6 divided by 6=1

96km:1hr

96 was the coaches speed limit

km=Kilometers

Hrs=Hours

96>90

6 0

3 years ago

A sanitary landfill has available space of 16.2 ha at an average depth of 10 m. Seven hundred sixty-five (765) cubic meters of s

AfilCa [17]

Answer:

16.3 years

Step-by-step explanation:

1 ha = 10,000 m^2

The total capacity of the landfill is:

$C = 16.2*10,000*10 = 1,620,000\ m^3$

If waste is compacted to twice its delivered density, its volume is half of the delivered volume. Assuming that a year has 52 weeks, the volume of compacted solid waste dumped per year is:

$V=52*(5*0.5*765)\\V=99,450\ m^3$

The expected life of the landfill is given by its capacity divided by the yearly volume:

$L=\frac{C}{V}=\frac{1,620,000}{99,450} \\L=16,3\ years$

The landfill has an expected life of 16.3 years.

6 0

3 years ago

Solve 0 = (x – 4)2 – 1 by graphing the related function.

fomenos

Answer:

Therefore, the solutions of the quadratic equations are:

$x=5,\:x=3$

The graph is also attached.

Step-by-step explanation:

The solution of the graph could be obtained by finding the x-intercept.

$y=\left(x-\:4\right)^2-1$

Finding the x-intercept by substituting the value y = 0

$y=\left(x-\:4\right)^2-1$

$\:0\:=\:\left(x\:-\:4\right)^2\:-\:1$ ∵ y = 0

$\left(x-4\right)^2-1=0$

$\left(x-4\right)^2-1+1=0+1$

$\left(x-4\right)^2=1$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$\mathrm{Solve\:}\:x-4=\sqrt{1}$

$\mathrm{Apply\:rule}\:\sqrt{1}=1$

$x-4=1$

$x=5$

$\mathrm{Solve\:}\:x-4=-\sqrt{1}$

$\mathrm{Apply\:rule}\:\sqrt{1}=1$

$x-4=-1$

$x=3$

So, when y = 0, then x values are 3, and 5.

Therefore, the solutions of the quadratic equations are:

$x=5,\:x=3$

The graph is also attached. As the graph is a Parabola. It is visible from the graph that the values of y = 0 at x = 5 and x = 3. As the graph is a Parabola.

8 0

3 years ago