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2 years ago

Help with this inequality pleaze

Mathematics

1 answer:

Eddi Din [679]2 years ago

3 0

Answer:

108 cm^2

Step-by-step explanation:

Trapezoid area = (a+b)/2 * h

= (6+12)/2 * 6 = 54 cm^2

Triangle area = b*h/2 = 12* (15-6) / 2 = 54 cm^2

Total area is 54+54 = 108 cm^2

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(2x+3y)+(8x+10y) simplify the following

zzz [600]

Answer:

10x+13y

Step-by-step explanation:

remove parentheses:

2x+3y+8x+10y

add like-terms:

2x+8x+3y+10y

add numbers with the same variables/elements

10x+3y+10y-->10x+13y

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3 years ago

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When adding fractions does the denominator stay the same?

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3 years ago

Which of the following systems of linear inequalities is represented by the

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Answer: B

Step-by-step explanation:

The line y=2 is solid and shaded above, so it represents $y \geq 2$ .

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2 years ago

I WIL GIVE BRAINILIEST IF YOU GIVE EXPLANATION FOR BOTH please dont let me fail

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1. 2/5

2. 2/5

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3 years ago

A conical water tank with vertex down has a radius of 13 feet at the top and is 21 feet high. If water flows into the tank at a

VLD [36.1K]

Answer:

$\frac{dh}{dt}\approx0.08622\text{ ft/min}$

Step-by-step explanation:

We know that the conical water tank has a radius of 13 feet and is 21 feet high.

We also know that water is flowing into the tank at a rate of 30ft³/min. In other words, our derivative of the volume with respect to time t is:

$\frac{dV}{dt}=\frac{30\text{ ft}^3}{\text{min}}$

We want to find how fast the depth of the water is increasing when the water is 17 feet deep. So, we want to find dh/dt.

First, remember that the volume for a cone is given by the formula:

$V=\frac{1}{3}\pi r^2h$

We want to find dh/dt. So, let's take the derivative of both sides with respect to the time t. However, first, let's put the equation in terms of h.

We can see that we have two similar triangles. So, we can write the following proportion:

$\frac{r}{h}=\frac{13}{21}$

Multiply both sides by h:

$r=\frac{13}{21}h$

So, let's substitute this in r:

$V=\frac{1}{3}\pi (\frac{13}{21}h)^2h$

Square:

$V=\frac{1}{3}\pi (\frac{169}{441}h^2)h$

Simplify:

$V=\frac{169}{1323}\pi h^3$

Now, let's take the derivative of both sides with respect to t:

$\frac{d}{dt}[V]=\frac{d}{dt}[\frac{169}{1323}\pi h^3}]$

Simplify:

$\frac{dV}{dt}=\frac{169}{1323}\pi \frac{d}{dt}[h^3}]$

Differentiate implicitly. This yields:

$\frac{dV}{dt}=\frac{169}{1323}\pi (3h^2)\frac{dh}{dt}$

We want to find dh/dt when the water is 17 feet deep. So, let's substitute 17 for h. Also, let's substitute 30 for dV/dt. This yields:

$30=\frac{169}{1323}\pi (3(17)^2)\frac{dh}{dt}$

Evaluate:

$30=\frac{146523}{1323}\pi( \frac{dh}{dt})$

Multiply both sides by 1323:

$39690=146523\pi\frac{dh}{dt}$

Solve for dh/dt:

$\frac{dh}{dt}=\frac{39690}{146523}\pi$

Use a calculator. So:

$\frac{dh}{dt}\approx0.08622\text{ ft/min}$

The water is rising at a rate of approximately 0.086 feet per minute.

And we're done!

Edit: Forgot the picture :)

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4 years ago