Question

Name the line of reflection used to map each pre-image to its image. Please help

Answer 1

Answer:

Step-by-step explanation:

From the picture attached,

9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.

    Therefore, line of reflection will be x = -2

10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,

y = x.

11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.

12). Line passing through midpoint of the line joining BB' will be the line of reflection.

Coordinates of B → (5, 3)

Coordinates of B' → (5, 7)

Coordinates of BB' → $(\frac{5+5}{2},\frac{3+7}{2})$ → (5, 5)

Therefore, line of reflection will be y = 5.

13). Coordinates of G → (2, 5)

     Coordinates of G' → (-2, 5)

     Midpoint joining the segment GG' → $(\frac{2-2}{2},\frac{5+5}{2})$ → (0, 5)

     Therefore, line of reflection → x = 0

14). Line of reflection passing through (0, 0) and slope = -1

     y = -x