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oee [108]
3 years ago
11

Last year, the average American used 167 disposable water bottles (16.9 oz or 0.132 gallons). If the cost of 1 gallon of tap wat

er in Philadelphia is approximately 7 cents, how much money could be saved by drinking tap water if we assume the cost of 1 bottle of water is $1.00?
Mathematics
1 answer:
Mrrafil [7]3 years ago
8 0

Answer:

The money that could be saved by drinking tap water is $165.46.

Step-by-step explanation:

Given:

Cost of 1 bottle of water = $1.00

Number of bottles consumed = 167

Volume of water used in 1 bottle = 0.132 gallons

So, volume of water used in 167 bottles = 167 × 0.132 = 22.04 gallons

Cost of 1 gallon of tap water = 7 cents = $0.07

In order to determine the money saved using tap water, we first find the cost of 167 bottles.

Using unitary method,

1 bottle cost = $1.00

167 bottles cost = Number of bottles × Cost of 1 bottle

                          = 167 × $1.00 = $167.00

Now, 167 dollars is spent for consuming 22.04 gallons of water.

Now, cost of 1 gallon of tap water = $0.07

So, cost of 22.04 gallons of tap water = 22.04 × 0.07 = $1.54

Therefore, the money saved by drinking tap water is given as:

Money saved = Money spent in bottles for 22.04 gallons - Money spent in tap water for the same volume

Money saved = $167.00 - $1.54 = $165.46

Hence, the money that could be saved by drinking tap water is $165.46.

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Write the equation of the line that passes through (-1, 3) and is parallel to the line y = -x + 1.
ra1l [238]

Answer:

Step-by-step explanation:

y = -x + 1......same as y = -1x + 1.....in y = mx + b form, ur slope is in the m position....so the slope of this line is -1.

a parallel line will have the same slope.

(-1,3)...x = -1 and y = 3

slope(m) = -1

y = mx + b.....we have x,y, and m....now we need to find y int (b)

3 = -1(-1) + b

3 = 1 + b

3 - 1 = b

2 = b

so ur parallel equation is : y = -1x + 2...or just y = -x + 2

7 0
3 years ago
What is the standard form of (2+3i)(4-7i)/(1-I)
AlladinOne [14]
I believe in standard form this would be 31/2 + 27i/2
8 0
3 years ago
Read 2 more answers
A bank with a branch located in a commercial district of a city has the business objective of developing an improved process for
tatiyna

Answer:

(a) The test statistic value is -4.123.

(b) The critical values of <em>t</em> are ± 2.052.

Step-by-step explanation:

In this case we need to determine whether there is evidence of a difference in the mean waiting time between the two branches.

The hypothesis can be defined as follows:

<em>H₀</em>: There is no difference in the mean waiting time between the two branches, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: There is a difference in the mean waiting time between the two branches, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

The data collected for 15 randomly selected customers, from bank 1 is:

S = {4.21, 5.55, 3.02, 5.13, 4.77, 2.34, 3.54, 3.20, 4.50, 6.10, 0.38, 5.12, 6.46, 6.19, 3.79}

Compute the sample mean and sample standard deviation for Bank 1 as follows:

\bar x_{1}=\frac{1}{n_{1}}\sum X_{1}=\frac{1}{15}[4.21+5.55+...+3.79]=4.29

s_{1}=\sqrt{\frac{1}{n_{1}-1}\sum (X_{1}-\bar x_{1})^{2}}\\=\sqrt{\frac{1}{15-1}[(4.21-4.29)^{2}+(5.55-4.29)^{2}+...+(3.79-4.29)^{2}]}\\=1.64

The data collected for 15 randomly selected customers, from bank 2 is:

S = {9.66 , 5.90 , 8.02 , 5.79 , 8.73 , 3.82 , 8.01 , 8.35 , 10.49 , 6.68 , 5.64 , 4.08 , 6.17 , 9.91 , 5.47}

Compute the sample mean and sample standard deviation for Bank 2 as follows:

\bar x_{2}=\frac{1}{n_{2}}\sum X_{2}=\frac{1}{15}[9.66+5.90+...+5.47]=7.11

s_{2}=\sqrt{\frac{1}{n_{2}-1}\sum (X_{2}-\bar x_{2})^{2}}\\=\sqrt{\frac{1}{15-1}[(9.66-7.11)^{2}+(5.90-7.11)^{2}+...+(5.47-7.11)^{2}]}\\=2.08

(a)

It is provided that the population variances are not equal. And since the value of population variances are not provided we will use a <em>t</em>-test for two means.

Compute the test statistic value as follows:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}}

  =\frac{4.29-7.11}{\sqrt{\frac{1.64^{2}}{15}+\frac{2.08^{2}}{15}}}

  =-4.123

Thus, the test statistic value is -4.123.

(b)

The degrees of freedom of the test is:

m=\frac{[\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}]^{2}}{\frac{(\frac{s_{1}^{2}}{n_{1}})^{2}}{n_{1}-1}+\frac{(\frac{s_{2}^{2}}{n_{2}})^{2}}{n_{2}-1}}

   =\frac{[\frac{1.64^{2}}{15}+\frac{2.08^{2}}{15}]^{2}}{\frac{(\frac{1.64^{2}}{15})^{2}}{15-1}+\frac{(\frac{2.08^{2}}{15})^{2}}{15-1}}

   =26.55\\\approx 27

Compute the critical value for <em>α</em> = 0.05 as follows:

t_{\alpha/2, m}=t_{0.025, 27}=\pm2.052

*Use a <em>t</em>-table for the values.

Thus, the critical values of <em>t</em> are ± 2.052.

3 0
3 years ago
MELISA SELMIC
Zarrin [17]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
A
ludmilkaskok [199]

Answer:

25

Step-by-step explanation:

ABC is a right angle so ABD and DBC are <em>complementary angles</em> and their sum is equal to 90:

x + 55 = 90 subtract 55 from both sides

x = 25

6 0
2 years ago
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