1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
oksano4ka [1.4K]
3 years ago
5

The faces of a cube are to be numbered with integers 1 through 6 in such a way that consecutive numbers are always on adjacent f

aces (not opposite ones). The face numbered 1 is on top and the face numbered 2 is toward the front. In how many different ways can the remaining faces be numbered?
Mathematics
1 answer:
Blizzard [7]3 years ago
7 0

Answer:

Total different ways to number the remaining faces is 10.

Step-by-step explanation:

It is given that consecutive numbers are always on adjacent faces (not opposite ones).

The face numbered 1 is on top and the face numbered 2 is toward the front.

Top = 1

Front = 2

The remaining faces are left right bottom back. Total possibilities are shown below.

S.no.      3                4              5               6

(1)       Right         Back         Bottom       Left  

(2)       Right         Back         Left         Bottom  

(3)       Right        Bottom       Left           Back  

(4)       Right        Bottom       Back         Left  

(5)       Bottom      Right         Back         Left  

(6)       Bottom       Left          Back        Right  

(7)       Left            Back       Bottom       Right  

(8)       Left            Back        Right         Bottom  

(9)       Left           Bottom      Right          Back  

(10)     Left            Bottom      Back         Right

When Bottom=3, then we can not place 4 on back because doing this 5 and 6 are opposite ones.

Therefore, total different ways to number the remaining faces is 10.

You might be interested in
Student identification codes at a high school are 4-digit randomly generated codes beginning with 1 letter and ending with 3 num
irinina [24]
\dfrac{1}{26,000}\approx3.8\%
4 0
3 years ago
Given: angle 1 is supplementary to angle 2 and angle 1 is congruent to angle 3.
gregori [183]
 ∠1 and ∠2 are supplementary    // given∠3 and ∠4 are supplementary    // given∠1 ≅ ∠3    // given m∠1 + m∠2 = 180°    // definition of supplementary anglesm∠3 + m∠4 = 180°    // definition of supplementary angles m∠1 + m∠2 = m∠3 + m∠4    // transitive property of equality m∠1 = m∠3    // definition of congruent angles m∠1 + m∠2 = m∠1 + m∠4    // substitution property of equality (replaced m∠3 with m∠1) m∠2 = m∠4    // subtraction property of equality (subtracted m∠1 from both sides) ∠2 ≅ ∠4    // definition of congruent angles


8 0
3 years ago
(Apex!) Select the two values of x that are roots of this equation 3x-5=-2x^2
katovenus [111]

Answer:

B and D

Step-by-step explanation:

Write as a quadratic

-2x² - 3x + 5 = 0

Factor

-2x² - 5x + 2x + 5 = 0

-x(2x + 5) + 1(2x + 5) = 0

(1 - x)(2x + 5) = 0

To make the equation 0, x is either 1 or -5/2.

4 0
3 years ago
8 x(11-3) + 9 with and exponent of 2
lesya692 [45]

Answer:

73

Step-by-step explanation:

first u have to subtract 11 and 3 with is 8 and then you have to multiply 8 times 8 which is 64 aqnd then plus 9 and there u get 73

6 0
3 years ago
Read 2 more answers
HELP ASAP : Find the largest value of n such that 5x^2+nx+48 can be factored as the product of two linear factors with integer c
Anna71 [15]

Answer:

n=241

Step-by-step explanation:

We are given

5x^2+nx+48

Let's assume it can be factored as

5x^2+nx+48=(5x-s)(x-r)

now, we can multiply right side

and then we can compare it

5x^2+nx+48=5x^2-5rx-sx+rs

5x^2+nx+48=5x^2-(5r+s)x+rs

now, we can compare coefficients

rs=48

5r+s=-n

n=-(5r+s)

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

48=-+(1\times 48)

48=-+(2\times 24)

48=-+(3\times 16)

48=-+(4\times 12)

48=-+(6\times 8)

Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

so, we get

n=-(5\times -48-1)

n=241


7 0
3 years ago
Other questions:
  • Solve the inequality and write down the solution in interval notation x(x-3)(x+1)<0
    6·1 answer
  • Please answer number 1
    13·1 answer
  • Use the steps to finish writing an equivalent equation for y in terms of x. −6x = 12 − 4y 1.  Subtract 12 from both sides: −6x −
    11·2 answers
  • Paula walked 4.5 miles. How many kilometers did Paula walk? I mile = 1.61 kilometers
    14·1 answer
  • An experiment was designed to measure how long subjects could track a moving target on a computer screen. The target moved errat
    15·1 answer
  • Let K and T be the current ages of two siblings Katie and Thomas Katie is currently twice the age of Thomas. In 6 years Katie wi
    7·1 answer
  • Plz help with this I would mean a lot...Thanks!
    11·2 answers
  • Which of the following graphs represents the solution set for y< -2x – 4? ​
    5·1 answer
  • Given: g(a) = 3a +2 and f(a)= a2 - 1<br> Find: f(a-1)= g(a-1)
    12·1 answer
  • ASAP!!! PLEASE HELPPP!!Write an equation for the following sentence, then solve for the unknown value.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!