To find this you know that the A of a square = s^2
So the length of one side equals
Since this is a perfect square, it would equal
And
Also you know it is a perfect square because the first and last terms are perfect squares :) :D
Answer:
y = x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (4, 7)
m = 
= 
= 1, hence
y = x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation.
Using (1, 4), then
4 = 1 + c ⇒ c = 4 - 1 = 3
y = x + 3 ← equation in slope- intercept form
A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
I can you be a little bit clear I don’t really understand the question.
