108 pencils to 27 students <br> What is the unit rate?

What will happen to the size of the population in the long run?

Irina-Kira [14]

I'm assuming there's a chart, but if there isn't,

The population will continue to increase and decrease, as the population will grow until it's reached its carrying capacity, and then decrease because there aren't enough resources, and then increase, then decrease, etc.

7 0

3 years ago

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago

NEED HELP ASAP

antoniya [11.8K]

answer= x=20

Step-by-step explanation:

We have, 35% × x = 7

or,

35

100

× x = 7

Multiplying both sides by 100 and dividing both sides by 35,

we have x = 7 ×

100

35

x = 20

If you are using a calculator, simply enter 7×100÷35, which will give you the answer.

5 0

2 years ago

Read 2 more answers

Find the slope of the line that passes through the coordinates (3,-6) and (-9,2)

JulsSmile [24]

9514 1404 393

Answer:

-2/3

Step-by-step explanation:

The slope formula is useful for this.

m = (y2 -y1)/(x2 -x1)

m = (2 -(-6))/(-9 -3) = 8/-12

m = -2/3

The slope of the line is -2/3.

__

The graph shows the two points and a line with a slope of -2/3.

4 0

3 years ago

What is 5/8 as a decimal?

bogdanovich [222]

Answer:

.625

Step-by-step explanation:

7 0

2 years ago

108 pencils to 27 students What is the unit rate?