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Andreas93 [3]
3 years ago
5

Which test point holds true for 2/5x-1/5y≥0

Mathematics
1 answer:
Bumek [7]3 years ago
4 0
With the picture I've provided above, you are able to see the graph for 2/5x - 1/5y greater than or equal to 0.

Looking at the graph, you are able to detect many points that can be true to this equation.

(5,1) could be one point.

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Answer:

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6 0
3 years ago
I need help with 13 on both pictures. The first picture is the answer and the second picture is the question not getting the ans
natita [175]

Problem 13

If we want to multiply (x^3-3x^2+2x) with (x^3-2x^2+x), then we can set up a diagram shown below. The terms are along the outside. The stuff inside is the result of multiplying each pair of outer terms.

  • Example: x^3 times x^3 = x^6 in the top left corner
  • Another example: 2x times x = 2x^2 in the bottom right corner.

This is known as the box method to keep track of all the terms multiplied.

Once the table is filled out, we add up each term inside the boxes. Combine like terms if possible. Notice that I color-coded the like terms (eg: the x^3 terms are in green boxes).

The final answer is x^6 - 5x^5 + 9x^4 - 7x^3 + 2x^2

6 0
2 years ago
Nate borrowed $62,000 at 9.4% interest per year if he owed a total of $910.90 in when he repaid the loan how many days do they k
OverLord2011 [107]
The formula for simple annual interest is:

I = Prt

where,

I = Interest accumulated = $910.90
P = Principal Amount = $62000
r = Interest rate = 9.4% = 0.094
t = time in years

Using the values in above equation, we get:

910.90 = 62000 x 0.094 x t

⇒ t = 910.90/(62000 x 0.094) = 0.156

This is the time in years. Since there are 365 days in a year, the time in days will be:

t = 0.156 x 365 = 57 (rounded to nearest day)

This means, Nate kept the borrowed money for 57 days
6 0
4 years ago
Using quadratic form 6x^2-8x+3=0
LenaWriter [7]

x=8+sqrt-8/12, x=8-sqrt-8/12

I think...

5 0
3 years ago
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