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mr Goodwill [35]
3 years ago
11

Find the value of 15c1

Mathematics
1 answer:
Natali [406]3 years ago
8 0

Answer:

The simple answer is 15 only

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Find 1 3/5 + 1 1/3 iready
Arisa [49]
20 plus 24
Divided by 15
Which gets you to
44 over 15 or 2 wholes and 14 over 15
5 0
2 years ago
Read 2 more answers
Simplify<br>1)5x+3=x+13<br>2)5/2x-1/X =1/6​
Artyom0805 [142]

Step-by-step explanation (Question 1):        

<u>Step 1: (Question 1): Subtract x from both sides.</u>

5x+3=x+13

5x+3−x=x+13−x

4x+3=13

<u>Step 2: (Question 1): Subtract 3 from both sides.</u>

4x+3−3=13−3

4x=10

<u>Step 3: (Question 1): Divide both sides by 4.</u>

4x/4 = 10/4

FIRST ANSWER: x = 5/2

Step-by-step explanation (Question 2):      

<u>Step 1: (Question 2): Multiply by LCM</u>

15x^2 - 6 = x

<u>Step 2: (Question 2): Solve 15x^2</u>

15x^2 - 6 = x:

x = 2/3

x = -3/5

<u>Step 3: (Question 2): Solve</u>

ANSWER: x=0.666667 or x=−0.6

See Attachment 1 for question 1 steps (FULL)

See Attachment 2 for question 2 steps (FULL)

Answer:    

1)   x = 5/2

2)  x=0.666667 or x=−0.6

 

Hope this helps.

8 0
2 years ago
Read 2 more answers
If m\angle A=(6x+10)^{\circ}∠A=(6x+10) ∘ and m\angle B=(4x+30)^{\circ}∠B=(4x+30) ∘ , then find the measure of \angle B∠B.​
netineya [11]

A=6 × + 10=88555%__/455

6 0
2 years ago
Plz help me asap. Plz help help help
Leya [2.2K]
The answer is 10 because 9x5=45 then you do 45-15=30 then you divide by 3 which is 10.
Your welcome
5 0
2 years ago
34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
1 year ago
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