Answer:
f(1) = 16
Domain: 0 ≤ t ≤ 2
Step-by-step explanation:
Given
f(t) = -16t²+ 32t
Solving (a): f(1)
Substitute 1 for t in f(t)
f(t) =− 16t²+ 32t .
f(1) =− 16 * (1)²+ 32 * 1
f(1) = -16 * 1 + 32
f(1) = -16 + 32
f(1) = 16
Solving (b): The domain
The implication of the given parameter in (b) is that t ≤ 2.
Since t represents time, t can't be negative.
Hence, a reasonable domain is
0 ≤ t ≤ 2
Answer:
False.
Since the number of numbers in the world is infinite, there can be an infinite number of equivalent fractions.
When solving these proportions we just remember when moving a number from one side to the other if it started in the numerator it ends up in the denominator and vice versa.
I'll do it in two steps here for teaching purposes; it's not too hard to go directly to the answer.
Answer:
B 125. its basically 5 cubed
Step-by-step explanation:
5 times 5 times 5
After demonstrating the procedure by algebraic means, the expression ![(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )](https://tex.z-dn.net/?f=%282%5Csqrt%5B3%5D%7B12%7D%20%29%5Ccdot%20%283%5Csqrt%5B3%5D%7B2%7D%20%29)
<em>is equivalent to</em> ![6\cdot \sqrt[3]{24}](https://tex.z-dn.net/?f=6%5Ccdot%20%5Csqrt%5B3%5D%7B24%7D)
.
In this question we proceed to <em>simplify</em> by <em>algebraic</em> means into a <em>single</em> <em>radical</em> expression when possible, whose procedure is shown below and explained by appropriate definitions and theorems:
- Given.
-
![(2\cdot 3) \cdot (\sqrt[3]{12} \cdot \sqrt[3]{2} )](https://tex.z-dn.net/?f=%282%5Ccdot%203%29%20%5Ccdot%20%28%5Csqrt%5B3%5D%7B12%7D%20%5Ccdot%20%5Csqrt%5B3%5D%7B2%7D%20%20%29)
Commutative property/ Associative property. - Definition of cubic root/
![\sqrt[n]{a} = \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20%5Csqrt%5Bn%5D%7Bb%7D)
/Result
After demonstrating the procedure by algebraic means, the expression <em>is equivalent to</em> .
To learn more on radical expressions, we kindly invite to check this verified question: brainly.com/question/1810591
