4⋅(1/4^−3)+12 What would be the answer. Please helpp
2 answers:
You might be interested in
The value of 
, 
, and 
for each schools is given in the first picture below.
is the lower quartile
is the median
is the upper quartile
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
Answer:
Charlie is incoerre
Step-by-step explanation:
Given that :
Line of sight to top of flagpole = 16 feets
Angle of elevation = 60°
The height of the flagpole :
Applying trigonometry to the drawing in the attached picture :
We use:
Sinα = opposite / hypotenus
This enables us to use the value of the hypotenus (line of sight) to obtain the missing height value (h)
Sin(60°) = h / 16
h = 16 * sin 60
h = 16 * 0.8660254
h = 13.856406
Hence flagpole is about 13.86 feets high
Charlie's reasoning is incorrect, the line of sight constitutes the hypotenus and not Adjacent and hence, shoul
