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Arlecino [84]
1 year ago
13

Arrange the quantities in order from smallest to largest. 2.6 km​, 109,000 mm​, 41.7 hm

Mathematics
1 answer:
Aleksandr-060686 [28]1 year ago
4 0

The order of the values using the basic unit of meters from smallest to largest. is: 109000 mm < 2.6 km < 41.7 hm

What are the units of measurement of distance or length?

Distance is the gap between any two points under consideration.

The basic unit for measuring distance is the meter.

There are larger as well as smaller units for measuring length or distance which are based on the unit of meter.

The units are as follows:

millimeter, mm = 0.001 m

centimeter, cm = 0.01 m

decimeters, dm = 0.1 m

meter, m = 1 m

kilometer, km = 1000 m

hectometer, hm = 100 m

Now to compare the given quantities making the units same as two quantities can only be compared only when there units are same :

Considering the given values;

2.6 km = 2600 m

109,000 mm = 109 m

41.7 hm = 4170 m

Therefore, after comparison arranging the quantities in order from smallest to largest is 109000 mm < 2.6 km < 41.7 hm

Learn more about quantities at:

brainly.com/question/13421174

#SPJ1

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What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)? –2x + 5 2x – 5 –2x – 5 2x + 5
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ANSWER

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = - 2x+5

EXPLANATION

We have been given the quotient,

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} }
to simplify.

We need to rewrite the numerator as difference of two cubes.

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ {5}^{3} - ( {2x})^{3} }{ 25 + 10x + 4 {x}^{2} }

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Then the numerator becomes,

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)(25 + 5 (2x) + {(2x)}^{2}) }{ 25 + 10x + 4 {x}^{2} }

This simplifies to,

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)(25 + 10x + 4 {x}^{2}) }{ 25 + 10x + 4 {x}^{2} }

We cancel out common factors to obtain,

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)}{ 1}

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