Answer:
Step-by-step explanation:
-0.127
-0.12
0.20
0.33
45/10
I think that is right
Width: W
length: L = 5W
Use the Pyth. Theorem to find the length of the diagonal:
|D| = sqrt(W^2 + [5W]^2) = sqrt(W^2 + 25W^2) = sqrt(26W^2), or
Wsqrt(26) (ans.)
Answer:
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
5)
Adj = 14
Hyp = 26
∠X
so use
CAH
Cos(X) = 14/26
X = arcCos(14/26)
X = 57.421°
X = 57.4 ° ( rounded to nearest 10th )
6)
∠X
Hyp = 46
Opp = 12
use SOH
Sin(x) = 12/46
X = arcSin(12/46)
X = 15.121°
X = 15.1 ° ( rounded to nearest 10th )
7)
∠X
Adj = 29
Opp = 24
use TOA
Tan(x) = 29 / 24
X = arcTan( 29 /24)
X = 50.389
X = 50.4 ° ( rounded to nearest 10th )
8)
∠X
Adj = 22
Opp = 6
use TOA agian
Tan(x) = 6 / 22
X = arcTan(6/22)
X = 5.194
X = 5.2 ° ( rounded to the nearest 10th )
:)
The answer is D because 42 / 6 = 7 and the power ( ^X) can cancel out each other
