Answer:
x≥5
Step-by-step explanation:
3(x+15)≤5(x+2)+15
3x+45≤5x+10+15
3x+35≤5x+25
3x-5x≤25-35
-2x≤-10
x≥5
{x:xEx:6,7,8,9,10....}
Hope this helps ;) ❤❤❤
Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Answer:
it's 60 degree in my thinking
Step-by-step explanation:
hope this is the answer
20 times 5 is 100. We can multiply 2*5 and get 10, then add another zero to make it easier.