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nordsb [41]
3 years ago
12

Write an equation to match each graph:

Mathematics
2 answers:
morpeh [17]3 years ago
5 0

Write an equation to match each graph.

Solution:

The first graph is V shaped graph centered at origin, (0,0) and the graph is not shifted or translated. So, the equation of first graph is,

y=|x|

The second graph is V shaped graph centered at (1,0) and y=|x| is horizontally shifted right by 1 unit. So, the equation of second graph is,

y=|x-1|

The third  graph is also V shaped but, it is inverted V graph centered at (0,1) . As, the graph is inverted V So, the graph must have y=-|x|. But, as the center is (0,1). So, the graph is shifted up by 1 unit. So, the equation of the third graph is,

y=-|x|+1

The fourth graph is shifted V graph, whose center is (1,-1). So, y=|x| is shifted right by 1 unit and down by 1 unit. So, the equation of fourth graph is,

y=|x-1|-1

The center of fifth graph is (-1,0), So, y=|x| graph is shifted left by 1 unit. So, the equation of fifth graph is

y=|x+1|

Nikolay [14]3 years ago
3 0
The equation should be y=|x| BUT i am not 100%. there would be no shifts because the vertex is on the origin.
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<h3>Given:</h3>
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<h3>Note that:</h3>
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  • l: length
<h3>To find:</h3>
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<h3>Solution:</h3>
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\large\boxed{Formula: V= \frac{wl}{2}×h}

Let's solve!

First, let's multiply width and height.

6×6

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Now, we'll have to divide the answer by 2.

\frac{36}{2}

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Then, multiply the answer by length.

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<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>triangular</u><u> </u><u>prism</u><u> </u><u>is</u><u> </u><u>1</u><u>8</u><u>0</u><u> </u><u>cubic</u><u> </u><u>units</u><u>.</u>

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Answer:

Step-by-step explanation:

116f) 5 - |p + 6| = -8

       |p + 6| = 13

       p + 6 = 13          OR           p + 6 = -13

       p = 7                  OR           p = -19

In this case, I think you have to plot a point at 7 and -19.

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       7x = 5                OR             7x = -5

       x = \frac{5}{7}                   OR              x = -\frac{5}{7}

Again, I think you need to plot points at \frac{5}{7} and -\frac{5}{7}.

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