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alex41 [277]
2 years ago
5

HELPPP

Mathematics
1 answer:
ollegr [7]2 years ago
3 0

Answer:

1.25

Step-by-step explanation:

the scale factor is the ratio of corresponding sides, image to original, so

scale factor = \frac{EZ}{TR} = \frac{15}{12} = \frac{5}{4} = 1.25

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DUE IN 4 MINS help plsssssssssssss
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Answer:

B

Step-by-step explanation:

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Answer:

I uploaded a file hosting link for your question.

See below for more details.

Step-by-step explanation:

m=\frac{change(y)}{change(x)}

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Add three data values to the following data set so the mean increases by 10 but the median does not change. The numbers are 42 3
777dan777 [17]
In order the numbers are 20, 29, 32, 37, 42.
So that means the median is 32. In order for the median to stay the same one of the three data values must be 32 as well as adding a number to each side of the ends. One 32 or less another 32or more.
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Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
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