Answer:
Option B. 
Step-by-step explanation:
we know that
The area of a triangle is equal to
we have
Convert mixed numbers to an improper fractions
substitute the values
Answer:
opposite sides of a parallel are congruent.
Step-by-step explanation:
the symbol between AB and DC stands for "equal to", not parallel. boom roasted. (don't hate me if I'm wrong)
Answer:
Surface area = 663π in².
Volume = (676/3)π in² ≈ 225.33 π in²
Explanation:
1) We know the radius and the lateral area.
2) With the radius you can find the areas of the top and the bottom.
For that, you use the formula:
area of the top = area of the bottom = π r²
∴ π (13 in)² = 169π in² (each)
3) Then, the surface area is the sum of the lateral area and the two bases (top and bottom)
surface area = lateral area + bottom area + top area = 325π in² + 2×169π in² = 663π in².
3) You can also find the height of the cylinder.
Use the formula: lateral area = 2π r h
∴ h = lateral area / [2 π r]
⇒ h = 325 π / [ 2π (13) ] = 12.5 in
4) With the height you can find the volume.
Use the formula: V = (4/3) π r³
∴ V = (4/3) π (13 in)³ = (676/3)π in² ≈ 225.33 π in²
<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.
Answer:
you have to start with you b which in your problem is 5 so put a point at 5 on the y-axis on your graph. then with the M (the fraction numbers) you have to move either up or down depending if there is a negative number. so yours is 1/2 so then you would start at the 5 point and go up 1 and right 2 then you just keep repeating till you get a few points and can make a line then you just do the same thing for the other equation. start at 3 on the y-axis and then go up 3 and right 4 then just keep repeating till you get a few point and can create a line at the end the lines should cross each other like perpendicular lines
Step-by-step explanation:
hope this helps:)
