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DaniilM [7]
3 years ago
14

Rylee earns $5,4000 in her first year of teaching and earns a 3% increase in each successive year. Write a geometric series form

ula SN for Rylee's total earning over and years. Use this formula to find Rylee's total earnings for first 20 years of teaching to the nearest cent.
Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer: $1387800

Step-by-step explanation:

This is an sum of Arithmetic Progression with the formula

Sum of nth term

Sn = n/2( a + l ) --------------- 1

where l = a + ( n - 1 )d -------2

Now put (2) in 1

Sn = n/2{( a + a + (n - 1)d}

= n/2{( 2a + ( n -1 )d}

From the question

a = $5,4000 ( firs term )

d = 3% of $5,4000 ( common difference ), n = 20 years. Solution to question one therefore is.

First find 3% of $54000 = $1620, so the geometric series is

Sn = n/2{(2a + ( n - 1 )d

Second solution is substitution,

Sn. = 20/2 {(2 x 54000 + (20 -1)1620)}

= 10{ 108000 + 19 x 1620}

= 10{ 108000 + 30780 }

= 10{ 138780 }

= 1387800

Therefore, the total emoluments of Rylee for the past 20 years

= $1387800

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