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lapo4ka [179]
3 years ago
8

PWEASE HELP IF YOUBARE GOOD AT MATH

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0
<h3>Answer: 2</h3>

=========================================================

Explanation:

The function f(x) = -4x+1 is the same as y = -4x+1 where y = f(x)

Compare this to y = mx+b and we see the slope here is m = -4

---------

Now let's find the slope of g(x)

use the slope formula with any two rows you want. I'll pick on the last two rows.

m = (y2-y1)/(x2-x1)

m = (21-9)/(3-1)

m = 12/2

m = 6 is the slope of g(x)

---------

From here, we add the two slope values

(slope of f)+(slope of g) = -4+6 = 2

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Step-by-step explanation:

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uranmaximum [27]

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

Given

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable.

<h3>The magnitude of an earthquake</h3>

The magnitude of an earthquake is a measure of the energy it releases.

For an earthquake with 1,000 times more intense than a standard earthquake.

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is;

\rm M =log \dfrac{I}{S}\\\\M = log \dfrac{10s}{s}\\\\M=log 10\\\\M =1

Hence, the equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

To know more about the magnitude of earthquakes click the link given below.

brainly.com/question/1337665

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