Calvin is building a fence. The fence will enclose a 100 square foot area, 10 ft wide by 10 ft long. Calvin can put fence posts
1 answer:
Answer:
20 fence posts.
Step-by-step explanation:
Calvin is building a fence. The fence will enclose a 100 square foot area, 10 ft wide by 10 ft long. Calvin can put fence posts 2 feet apart.
Now, if he puts a fence post at each corner of the building, then considering each length of the building there will be posts along each length.
Now, considering each width of the building there will be posts (excluding the corner posts) along each width.
Therefore, in total there will be (6 + 6 + 4 + 4) = 20 fence post in the total fence. (Answer)
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<h3>Answer:</h3>
- -100x +100; 3
- 5x +81; 162
The distributive property is your friend. It tells you ...
a(b + c) = ab + ac
It can also be used to simplify the product of binomials (or other polynomials).
(a +b)^2 = (a +b)(a +b) = a(a +b) + b(a +b) = a^2 +ab +ab +b^2
(a +b)^2 = a^2 +2ab + b^2 . . . . . . . worth remembering
1. (x -10)^2 -x(x +80) = (x^2 -20x +100) +(-x^2 -80x)
= -100x +100 . . . . . . simplified form
For the purposes of calculation, it can be easier to factor out 100:
= 100 (1 -x)
Then for x = 0.97
= 100(1 -0.97) = 100(0.03) = 3
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2. (2x +9)^2 -x(4x +31) = (4x^2 +36x +81) -4x^2 -31x = 5x +81
For x = 16.2, this is ...
5(16.2) +81 = 81 +81 = 162
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The purpose of the attachment is to show the evaluation is correct.