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3 years ago

What’s the answer to this please, thanks!

Mathematics

1 answer:

Bumek [7]3 years ago

3 0

Answer:

8 < x < 16

Step-by-step explanation:

Consider an angle slightly less than 180 between the 4 and 12 ft sides. The measure between the 2 end points is slightly less than the total of the two sides. So the greatest length is 16.

Consider an angle slightly more than 0 between the 4 and 12 ft sides. The measure between the 2 end points is slightly more than the difference between the two sides. So the lowest length is 8.

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Find the points at which the graph of the equation -4y=15-5x crossed the x- axis and the y - axis.

Lynna [10]

Answer:

see explanation

Step-by-step explanation:

Where the graph crosses the x- axis the y- coordinate is zero.

Let y = 0 in the equation and solve for x

- 4(0) = 15 - 5x, that is

15 - 5x = 0 ( subtract 15 from both sides )

- 5x = - 15 ( divide both sides by - 5 )

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Where the graph crosses the y- axis the x- coordinate is zero.

Let x = 0 in the equation and solve for y

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3 years ago

Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2

kotykmax [81]

Answer:

$2\frac{1}{6}\approx 2.167$ units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

$\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}$

$\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}$

Let us have a common denominator.

$\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}$

$\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{13}{6}$

$\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}$

Therefore, Joy traveled $2\frac{1}{6}\approx 2.167$ units in 5 days.

8 0

4 years ago