All categories

3 years ago

If (x, 0) lies on the graph of y = logbx, then x =

Mathematics

2 answers:

anygoal [31]3 years ago

7 0

Answer:

$\text{The required value of x = }\frac{1}{b}$

Step-by-step explanation:

The function which is representing the graph is given to be : y = log (bx)

Now, as given the point (x,0) lies on the given graph

And if a point lies on a graph then the point satisfies the corresponding equation of the graph.

⇒ (x,0) satisfies the equation of the given graph.

⇒ (x,0) satisfies the equation : y = log (bx)

⇒ 0 = log (bx)

⇒ bx = 1

$\implies x=\frac{1}{b}$

$\text{Hence, The required value of x = }\frac{1}{b}$

Fittoniya [83]3 years ago

3 0

We have the following expression:
y = logbx
We clear x of the expression.
We have then:
b ^ y = b ^ (logbx)
Rewriting:
x = b ^ y
Substituting we have:
x = b ^ 0
x = 1
Answer:
If (x, 0) lies on the graph of y = logbx, then:
x = 1

You might be interested in

3.625 x 10−4<br> Question 2 options:<br><br> .3625<br><br><br> 36,250<br><br><br> 0.0003625

disa [49]

Answer:

0.0003625

:) Hope that helps :)

3 0

3 years ago

What is the range of y = –3sin(x) – 4?

nydimaria [60]

Answer:

The required range of the function $y=-3\sin (x)-4$ is [-7,-1]

Step-by-step explanation:

Given : Function $y=-3\sin (x)-4$

To find : What is the range of the given function?

Solution :

The range is defined as the variation in which any function is defined.

We know that the sin function lies between [-1,1]

$-1\leq \sin x\leq 1$ .....(1)

The required function is $y=-3\sin (x)-4$

Multiply equation (1) by -3

$-3\leq -3\sin x\leq 3$ .....(2)

Now, we subtract equation (2) by 4

$-3-4\leq -3\sin x-4\leq 3-4$

$-7\leq -3\sin x-4\leq -1$

Therefore, The required range of the function $y=-3\sin (x)-4$ is [-7,-1].

3 0

4 years ago

Read 2 more answers

Sonja plays tennis and started a tournament with 43 aces on the season. The graph relates her total season aces with the number

Pani-rosa [81]

<h2>Answer</h2>

$-6x+y=43$

<h2>Explanation</h2>

The first thing we need to do is find the slope of our line. To do it we are using the slope formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

where

$m$ is the slope of the line

$(x_{1},y_{1})$ are the coordinates of the first point on the line

$(x_{2},y_{2})$ are the coordinates of the second point

From our graph we can get the points (0, 43) and (2, 55), so $x_{1}=0$ , $y_{1}=43$ , $x_{2}=2$ , and $y_{2}=55$ . Let's replace the values in our slope formula:

$m=\frac{55-43}{2}$

$m=\frac{12}{2}$

$m=6$

Now that we have our slope, we can use the point-slope formula:

$y-y_{1}=m(x-x_{1})$

$y-43=6(x-0)$

$y-43=6x$

But remember that the equation of a line in standard form is $Ax+Ay=C$ , so we need to subtract $6x$ and add 43 to both sides of our point slope equation: