Question

If (x, 0) lies on the graph of y = logbx, then x =

Answer 1

Answer:

$\text{The required value of x = }\frac{1}{b}$

Step-by-step explanation:

The function which is representing the graph is given to be : y = log (bx)

Now, as given the point (x,0) lies on the given graph

And if a point lies on a graph then the point satisfies the corresponding equation of the graph.

⇒ (x,0) satisfies the equation of the given graph.

⇒ (x,0) satisfies the equation : y = log (bx)

⇒ 0 = log (bx)

⇒ bx = 1

$\implies x=\frac{1}{b}$

$\text{Hence, The required value of x = }\frac{1}{b}$

Answer 2

We have the following expression:
 y = logbx
 We clear x of the expression.
 We have then:
 b ^ y = b ^ (logbx)
 Rewriting:
 x = b ^ y
 Substituting we have:
 x = b ^ 0
 x = 1
 Answer:
 If (x, 0) lies on the graph of y = logbx, then:
 x = 1