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sasho [114]
3 years ago
15

If (x, 0) lies on the graph of y = logbx, then x =

Mathematics
2 answers:
anygoal [31]3 years ago
7 0

Answer:

\text{The required value of x = }\frac{1}{b}

Step-by-step explanation:

The function which is representing the graph is given to be : y = log (bx)

Now, as given the point (x,0) lies on the given graph

And if a point lies on a graph then the point satisfies the corresponding equation of the graph.

⇒ (x,0) satisfies the equation of the given graph.

⇒ (x,0) satisfies the equation : y = log (bx)

⇒ 0 = log (bx)

⇒ bx = 1

\implies x=\frac{1}{b}

\text{Hence, The required value of x = }\frac{1}{b}

Fittoniya [83]3 years ago
3 0
We have the following expression:
 y = logbx
 We clear x of the expression.
 We have then:
 b ^ y = b ^ (logbx)
 Rewriting:
 x = b ^ y
 Substituting we have:
 x = b ^ 0
 x = 1
 Answer:
 
If (x, 0) lies on the graph of y = logbx, then:
 
x = 1
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