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algol [13]
3 years ago
14

What is the slope and y- intercept of the gtaoh of each equation Y=-x-1

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0
Slope is -1 That's the value in front of X
Yintercept is -1. The number after x
You might be interested in
Please I need the correct answer please
Rzqust [24]

(<u>−1</u>

2  )(n^3)+

<u>1</u>

2 n^2+4.6n+(−

<u>1</u>

2)(n^3)+

<u>1</u>

2  n^2+4.5n

=

<u>−1</u>

2  n^3+

1

2  n^2+4.6n+

−1

2  n^3+

1

2  n^2+4.5n

Combine Like Terms:

=

<u>−1</u>

2  n^3+

<u>1</u>

2  n^2+4.6n+

<u>−1</u>

2  n^3+

<u>1</u>

2  n^2+4.5n

=(<u>−1</u>

  2   n^3+

<u>−1</u>

2   n^3)+(

<u>1</u>

2  n^2+

<u>1</u>

2   n^2)+(4.6n+4.5n)

=−n^3+n^2+9.1n

Answer:

=−n^3+n^2+9.1n

     Everything underlined means its a  fraction/divided hope this helps <em>:D</em>

8 0
3 years ago
Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. F(x) =
Troyanec [42]

Answer:

a) P (x <= 3 ) = 0.36

b) P ( 2.5 <= x <= 3  ) = 0.11

c) P (x > 3.5 ) = 1 - 0.49 = 0.51

d) x = 3.5355

e) f(x) = x / 12.5

f) E(X) = 3.3333

g) Var (X) = 13.8891  , s.d (X) = 3.7268

h) E[h(X)] = 2500

Step-by-step explanation:

Given:

The cdf is as follows:

                           F(x) = 0                  x < 0

                           F(x) = (x^2 / 25)     0 < x < 5

                           F(x) = 1                   x > 5

Find:

(a) Calculate P(X ≤ 3).

(b) Calculate P(2.5 ≤ X ≤ 3).

(c) Calculate P(X > 3.5).

(d) What is the median checkout duration ? [solve 0.5 = F()].

(e) Obtain the density function f(x). f(x) = F '(x) =

(f) Calculate E(X).

(g) Calculate V(X) and σx. V(X) = σx =

(h) If the borrower is charged an amount h(X) = X2 when checkout duration is X, compute the expected charge E[h(X)].

Solution:

a) Evaluate the cdf given with the limits 0 < x < 3.

So, P (x <= 3 ) = (x^2 / 25) | 0 to 3

     P (x <= 3 ) = (3^2 / 25)  - 0

     P (x <= 3 ) = 0.36

b) Evaluate the cdf given with the limits 2.5 < x < 3.

So, P ( 2.5 <= x <= 3 ) = (x^2 / 25) | 2.5 to 3

     P ( 2.5 <= x <= 3  ) = (3^2 / 25)  - (2.5^2 / 25)

     P ( 2.5 <= x <= 3  ) = 0.36 - 0.25 = 0.11

c) Evaluate the cdf given with the limits x > 3.5

So, P (x > 3.5 ) = 1 - P (x <= 3.5 )

     P (x > 3.5 ) = 1 - (3.5^2 / 25)  - 0

     P (x > 3.5 ) = 1 - 0.49 = 0.51

d) The median checkout for the duration that is 50% of the probability:

So, P( x < a ) = 0.5

      (x^2 / 25) = 0.5

       x^2 = 12.5

      x = 3.5355

e) The probability density function can be evaluated by taking the derivative of the cdf as follows:

       pdf f(x) = d(F(x)) / dx = x / 12.5

f) The expected value of X can be evaluated by the following formula from limits - ∞ to +∞:

         E(X) = integral ( x . f(x)).dx          limits: - ∞ to +∞

         E(X) = integral ( x^2 / 12.5)    

         E(X) = x^3 / 37.5                    limits: 0 to 5

         E(X) = 5^3 / 37.5 = 3.3333

g) The variance of X can be evaluated by the following formula from limits - ∞ to +∞:

         Var(X) = integral ( x^2 . f(x)).dx - (E(X))^2          limits: - ∞ to +∞

         Var(X) = integral ( x^3 / 12.5).dx - (E(X))^2    

         Var(X) = x^4 / 50 | - (3.3333)^2                         limits: 0 to 5

         Var(X) = 5^4 / 50 - (3.3333)^2 = 13.8891

         s.d(X) = sqrt (Var(X)) = sqrt (13.8891) = 3.7268

h) Find the expected charge E[h(X)] , where h(X) is given by:

          h(x) = (f(x))^2 = x^2 / 156.25

  The expected value of h(X) can be evaluated by the following formula from limits - ∞ to +∞:

         E(h(X))) = integral ( x . h(x) ).dx          limits: - ∞ to +∞

         E(h(X))) = integral ( x^3 / 156.25)    

         E(h(X))) = x^4 / 156.25                       limits: 0 to 25

         E(h(X))) = 25^4 / 156.25 = 2500

8 0
3 years ago
6k+4k&lt;-4k+6 solve for k
Genrish500 [490]

Answer:

k < 3/7

Step-by-step explanation:

Step 1:Sinplify both sides of the inequality

10k <-4k+6

Step 2: Add 4k to both sides

10k + 4k < -4k + 6 + 4k

14k < 6

Step 3:Divide both sides by 14

14k/14 < 6/14

k <3/7

Note:Provided by Mathpapa an Algebra caculator

6 0
2 years ago
PLEASE HELP !!! I WILL REWARD BRAINLIEST
icang [17]
First what is the formula for a cone, and just simplify
4 0
3 years ago
42+30=[BLANK](7+5)<br> 20 POINTS!!
qaws [65]

Answer:

42+30=72

7+5=12

72-12=60

Blank=60

Step-by-step explanation:

4 0
3 years ago
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