Answer:
c. 55.4 ft/s
Step-by-step explanation:
Speed of the object is represented by the function:

where x represents the number of feet the object has fallen. We have to find the speed of the object after it has fallen 48 feet. This means we have to find f(x) for x = 48. Substituting x = 48 in above equation we get:

Thus, rounded to nearest tenth, the speed of the object after it has fallen 48 feet would be 55.4 ft/s
Answer:
$251
Step-by-step explanation:
To get this amount, we simply find o.4% of 250.
That equals 0.4/100 × 250 = 1.
This means she would have earned an interest amounting to $1 after the first month.
The total amount of money in her account after the first month = 250 + 1 = 251
Hence, she would have an amount of $251 in her account after the first month.
Answer:
Step-by-step explanation:
Request of activities so increase then division, at that point deduction and expansion.
9*8 = 72
72/2 = 36
72-3 = 69
69+36 = 105
Another way of saying it is:
Utilize the request for tasks to improve on mathematical articulations. The request is brackets, types and roots, augmentation and division, expansion and deduction. Duplication and division are "something similar" so you would utilize the first that happens from left to right.
Bit by bit clarification:
7^2 - 3 + 9 x 8 ÷ 2
49 - 3 + 9 x 8 ÷ 2
49 - 3 + 72 ÷ 2
49 - 3 + 36
49 - 39
W=10
Brainliest?
bearing in mind that "a" is the length of the traverse axis, and "c" is the distance from the center to either foci.
we know the center is at (0,0), we know there's a vertex at (-48,0), from the origin to -48, that's 48 units flat, meaning, the hyperbola is a horizontal one running over the x-axis whose a = 48.
we also know there's a focus point at (50,0), that's 50 units from the center, namely c = 50.
![\bf \textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2}\\ \textit{asymptotes}\quad y= k\pm \cfrac{b}{a}(x- h) \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%5C%5C%20%5Ctextit%7Basymptotes%7D%5Cquad%20y%3D%20k%5Cpm%20%5Ccfrac%7Bb%7D%7Ba%7D%28x-%20h%29%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
