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wariber [46]
4 years ago
11

Andy, Brenda, and Carla are running in a race. In how many different ways can the students finish in first, second, and third pl

ace?
A) 2 ways
B) 3 ways
C) 4 ways
D) 6 ways
HELP ME PLS!!!
Mathematics
2 answers:
Sloan [31]4 years ago
8 0
D. 6 ways
1. Andy, Brenda, Carla
2. Andy, Carla, Brenda
3. Brenda, Carla, Andy
4. Brenda, Andy, Carla
5. Carla, Andy, Brenda
6. Carla, Brenda, Andy

nikklg [1K]4 years ago
7 0

First place can be any one of the 3 competitors.    For each of those . . .
Second place can be either one of the 2 remaining.   For each of those . . .
Third place is the  1  remaining runner.

Total number of possibilities = (3 x 2 x 1) = <em>6</em> .

Here are all the possible ways they can finish:

1). A B C
2). A C B
3). B A C
4). B C A
5). C A B
6). C B A


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inn [45]

Answer:

<u>Part A</u>:

x\in \mathbb{R} (x is equal to all real numbers)

<u>Part B</u>:

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Step-by-step explanation:

<u>Part A</u>:

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Add 7 to both sides:

x=x

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Therefore,

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<u>Part B</u>:

Using arbitrary values x=-4, x=0, x=5 as requested in part B, verify:

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Answer:

What is ur book called

I will edit my answer after this

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