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maria [59]
3 years ago
15

Solve 3(4m - 6) = 12 and explain each step

Mathematics
1 answer:
Studentka2010 [4]3 years ago
3 0
Distribute the 3 to 4m and 6. this makes 12m-18=12
now add 18 to both sides.
12m=30
now divide by 12
m=30/12
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Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball
Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0
4 years ago
1. tan a = cot(a + 10°)
Temka [501]

Answer:

a=40+90n

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So \tan(a)=\cot(90-a).

We have the equation:

\tan(a)=\cot(a+10)

Make the above replacement:

\cot(90-a)=\cot(a+10)

Since cotangent has period 180 degrees, we can also write this as:

\cot(90-a+180n)=\cot(a+10)

So solving the following will give us a set of solutions for a:

90-a+180n=a+10

Add a on both sides:

90+180n=2a+10

Subtract 10 on both sides:

80+180n=2a

Divide both sides by 2:

40+90n=a

Symmetric property:

a=40+90n

7 0
3 years ago
How many 6 digit different locker combinations are possible if no repeat numbers are allowed?
Alex_Xolod [135]

Since we are trying to find the number of sequences can be made <em>without repetition</em>, we are going to use a combination.


The formula for combinations is:

_n C _k = \dfrac{n!}{k! (n - k)!}

  • n is the total number of elements in the set
  • k is the number of those elements you are desiring

Since there are 10 total digits, n = 10 in this scenario. Since we are choosing 6 digits of the 10 for our sequence, k = 6 in this scenario. Thus, we are trying to find _{10} C _6. This can be found as shown:

_{10} C _6 = \dfrac{10!}{6! \cdot 4!} = \dfrac{10 \cdot 9 \cdot 8 \cdot 7}{4!} = \dfrac{5040}{24} = 210


There are 210 total combinations.

7 0
3 years ago
What is the slope of any line that is perpendicular to the line = y - 5 = 3/2 * (x + 1)
klio [65]

Answer:

-2/3

Step-by-step explanation:

6 0
2 years ago
Help pls my brain be broken​
Dmitry_Shevchenko [17]

Answer:

if it says n- -10 then its 10

if it says n-10 then its 30

Step-by-step explanation:

i dont know if that line is a negative

8 0
3 years ago
Read 2 more answers
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