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Alinara [238K]
3 years ago
8

If the translation of (x,y)->(x-5, y+2) was applied to the triangle ABC below, what would be the coordinates for A' after the

translation?
(0, 4)(0, -3)(4, -7) (-3, 0)

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0

Answer: (-3,0)

To get this answer, we subtract 5 from the x coordinate and add 2 to the y coordinate. Point A is located at (x,y) = (2,-2) so we see that x = 2 and y = -2

Subtract 5 from the x coordinate: x-5 = 2-5 = -3. The new x coordinate is -3

Add 2 to the y coordinate: y+2 = -2+2 = 0. The new y coordinate is 0.

Therefore, using the rule (x,y) --> (x-5,y+2) has the mapping (2,-2) ---> (-3,0)

Check out the attached image.


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-x+268=57 solve for x
Sergeeva-Olga [200]
Your answer would be x =211
7 0
3 years ago
PLEASE HELP
Sergeeva-Olga [200]

Answer:

y = 2

Step-by-step explanation:

I will solve this problem, using the elimination method.

-2(5x - 3y) = -11

-10x + 6y = 22

2x - 6y = -14

Subtract and divide for x

-8x = 8

x = -1

Input -1 into the equations

2(-1) - 6y = -14

-6y - 2 = -14

-6y = -12

y = 2

Thanks!

5 0
3 years ago
Simplify: 18q2−45q+25/9q2−25.
Svet_ta [14]

Answer:

\frac{(6q-5)}{(3q+5)}

Step-by-step explanation:

Given: \frac{18q^{2}-45q+25 }{9q^{2}-25 }

Factorizing the numerator and the denominator, we have:

18q^{2} - 45q + 25 = 18q^{2} - 30q - 15q + 25

                         = (3q - 5)(6q - 5)

and

9q^{2} - 25 = (3q - 5)(3q + 5)

So that,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}

                 = \frac{(6q-5)}{(3q+5)}

Therefore,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(6q-5)}{(3q+5)}

5 0
3 years ago
Write the equation of the parabola below
lorasvet [3.4K]
Answer:
Equation is: y = 0.5x² + 0.5x - 3

Explanation:
general form of the parabola is:
y = ax² + bx + c

Now, we will need to solve for a, b and c.
To do this, we will simply get points from the graph, substitute in the general equation and solve for the missing coefficients.

First point that we will use is (0,-3). 
y = y = ax² + bx + c
-3 = a(0)² + b(0) + c
c = -3

The equation now becomes:
y = ax² + bx - 3

The second point that we will use is (2,0):
y = ax² + bx - 3
0 = a(2)² + b(2) - 3
0 = 4a + 2b -3
4a + 2b = 3
This means that:
2b = 3 - 4a
b = 1.5 - 2a ...........> I

The third point that we will use is (-3,0):
y = ax² + bx - 3
0 = a(-3)² + b(-3) - 3
0 = 9a - 3b - 3
9a - 3b = 3 ...........> II

Substitute with I in II and solve for a as follows:
9a - 3b = 3
9a - 3(1.5 - 2a) = 3
9a - 4.5 + 6a = 3
15a = 7.5
a = 7.5 / 15
a = 0.5

Substitute with the value of a in equation I to get b as follows:
b = 1.5 - 2a 
b = 1.5 - 2(0.5)
b = 0.5

Substitute with a and b in the equation as follows:
y = 0.5x² + 0.5x - 3

Hope this helps :)
7 0
3 years ago
Which is equivalent to “12 chairs for every 3 tables”?
choli [55]

Answer:D. -4


Step-by-step explanation:

If the relationship is proportional, what is the missing value from the table?

X Y

-3 -1

-12 ?

-30 -10



7 0
2 years ago
Read 2 more answers
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