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tester [92]
3 years ago
9

What value of p makes the equation true? ​

Mathematics
2 answers:
Trava [24]3 years ago
7 0

Answer:

The value of p is -20

Step-by-step explanation:

From the question in the figure above;

\frac{3}{5}   p   +   \frac{1}{5}(40 - p)   =    0

we will have to make p subject of the formula

To do that, lets re-arrange the equation

\frac{3p}{5}  +  \frac{40 - p}{5}    =   0

This equation can be rearrange to become;

\frac{3p + 40 - p}{5}   =   0

Now, multiply both-side of the equation by 5. This will help us get rid of the 5 on the left hand side of the equation.

The equation becomes;

3p  +    40  - p  =   0

3p  -  p +  40  = 0

2p  + 40  = 0

subtract both-side of the equation by 40

2p  +  40 -40  =  0 -40

2p   =   -40

Divide both-side of the equation by 2

\frac{2p}{2}   =     \frac{-40}{2}

On the left hand side of the equation, the 2 in the numerator will cance that of the denominator

p = \frac{-40}{2}

p =     - 20

Therefore p =-20 makes the equation true  

AfilCa [17]3 years ago
7 0

Answer:

-20

Step-by-step explanation:

3/5 ×-20+1/5(40--20)

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<img src="https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Cbold%7B%5Cunderline%7B%5Cunderline%7BQuestion%3A%7D%7D%7D%7D" id="TexForm
Ronch [10]

Answer:

<h2> </h2><h2>{1024t}^{5}  - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2}   + 1620t-  243</h2>

Step-by-step explanation:

<h3><em><u>Question</u></em><em><u>:</u></em><em><u>-</u></em></h3>
  • To find the Binomial theorem form of \bold{(4t-3)^{5}}
<h3><em><u>As</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>know</u></em><em><u>:</u></em><em><u>-</u></em></h3>

<em>As</em><em> </em><em>in</em><em> </em><em>Bin</em><em>omial</em><em> </em><em>theorem</em><em> </em><em>:</em><em>-</em>

  • {(x - y)}^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}
<h3><em><u>Solution</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em></h3>

= {(4t - 3)}^{5}

  • <em>Hence</em><em>,</em><em> </em><em>on</em><em> </em><em>using</em><em> </em><em>the</em><em> </em><em>Binomial</em><em> </em><em>theorem</em><em>,</em><em> </em>

=  {(4t)}^{5}  - 5 {(4t)}^{4} (3)+ 10 {(4t)}^{3}  {(3)}^{2}  - 10 {(4t)}^{2}  {(3)}^{3}  + 5(4t) {(3)}^{4}  -  {(3)}^{5}

  • <em>On</em><em> </em><em>formatting</em><em> </em>

=  {1024t}^{5}  - 5 ({256t}^{4} )(3)+ 10 ({64t}^{3} ) (9 ) - 10 ({16t}^{2}  )(27)  + 5(4t) (81) -  243

  • <em>On</em><em> </em><em>further</em><em> </em><em>formatting</em><em>.</em><em> </em>

=  {1024t}^{5}  - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2}   + 1620t-  243

<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em>

{1024t}^{5}  - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2}   + 1620t-  243

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