Question

What value of p makes the equation true? ​

Answer 1

Answer:

The value of p is -20

Step-by-step explanation:

From the question in the figure above;

$\frac{3}{5} p$   +   $\frac{1}{5}(40 - p)$   =    0

we will have to make p subject of the formula

To do that, lets re-arrange the equation

$\frac{3p}{5}$  +  $\frac{40 - p}{5}$    =   0

This equation can be rearrange to become;

$\frac{3p + 40 - p}{5}$   =   0

Now, multiply both-side of the equation by 5. This will help us get rid of the 5 on the left hand side of the equation.

The equation becomes;

3p  +    40  - p  =   0

3p  -  p +  40  = 0

2p  + 40  = 0

subtract both-side of the equation by 40

2p  +  40 -40  =  0 -40

2p   =   -40

Divide both-side of the equation by 2

$\frac{2p}{2} = \frac{-40}{2}$

On the left hand side of the equation, the 2 in the numerator will cance that of the denominator

p = $\frac{-40}{2}$

p =     - 20

Therefore p =-20 makes the equation true  

Answer 2

Answer:

-20

Step-by-step explanation:

3/5 ×-20+1/5(40--20)